我有以下课程:
public interface MyInterface{}
public class MyImpl1 implements MyInterface{}
public class MyImpl2 implements MyInterface{}
public class Runner {
@Autowired private MyInterface myInterface;
}
我想要做的是在应用程序已经运行时(即启动时不)决定哪些实施应该注入Runner
。
理想情况是这样的:
ApplicationContext appContext = ...
Integer request = ...
Runner runner = null;
if (request == 1) {
//here the property 'myInterface' of 'Runner' would be injected with MyImpl1
runner = appContext.getBean(Runner.class)
}
else if (request == 2) {
//here the property 'myInterface' of 'Runner' would be injected with MyImpl2
runner = appContext.getBean(Runner.class)
}
runner.start();
实现这一目标的最佳方法是什么?
答案 0 :(得分:7)
使用@Component("implForRq1")
和@Component("implForRq2")
然后注入它们并使用:
class Runner {
@Autowired @Qualifier("implForRq1")
private MyInterface runnerOfRq1;
@Autowired @Qualifier("implForRq2")
private MyInterface runnerOfRq2;
void run(int rq) {
switch (rq) {
case 1: runnerOfRq1.run();
case 2: runnerOfRq2.run();
...
}
}
}
...
@Autowired
Runner runner;
void run(int rq) {
runner.run(rq);
}