Question

我是API和JSON的菜鸟，非常感谢以下任何帮助。我正在使用PHP Linkedin Library来运行People Queries。

以下是相关代码：

<?php
            $OBJ_linkedin->setResponseFormat(LINKEDIN::_RESPONSE_JSON);
            $keywords = (isset($_GET['keywords'])) ? $_GET['keywords'] : "Marketing";
            ?>
            <form action="<?php echo $_SERVER['PHP_SELF'];?>#peopleSearch" method="get">
                Search by Keywords: <input type="text" value="<?php echo $keywords?>" name="keywords" /><input type="submit" value="Search" />
            </form>
            <?php 
            $query    = '?sort=distance&current-company=true&keywords='.$keywords;
            $response = $OBJ_linkedin->searchPeople($query);

            if($response['success'] === TRUE) {


 echo "<pre>" . print_r($response['linkedin'], TRUE) . "</pre>";
            } else {
              // request failed
              echo "Error retrieving people search results:<br /><br />RESPONSE:<br /><br /><pre>" . print_r($response) . "</pre>";                
            }
          } else {
            // user isn't connected
            ?>

这是我得到的输出的摘录

{"people": {
  "_count": 10,
  "_start": 0,
  "_total": 11,
  "values": [
    {
      "firstName": "Peter",
      "headline": "Frontend Engineer at Lot18",
      "id": "kYZ3B2hHYH",
      "lastName": "Welch",
      "pictureUrl": "http://m.c.lnkd.licdn.com/mpr/mprx/0_e0hbvSXvhiSoTO2PERiqvfLV850d342PoOq4vakwx8IJOyR1XJrwRmr5mIx9C0DxWpGMsWVjBZEQ",
      "relationToViewer": {"distance": 3}
    },

  ]
}}

我想将“firstname”和“pictureUrl”等字段捕获到我可以在别处使用的变量中。例如。

<img src="<?php echo $picture-url; ?>" />

我该怎么做呢？我花了几天时间搜索/试图解决这个问题但仍然没有运气。任何帮助深表感谢！

Answer 1

响应格式是一个JSON对象，编码为字符串

$response['linkedin']

要取回对象，请使用：

$responseObject = json_decode($response['linkedin']);

然后你可以访问像这样的变量

$responseObject->values[0]->pictureUrl

将JSON数组值转换为变量（Linkedin PHP库）

1 个答案: