Question

我想让我的程序打印字母而不是数字。我使用char c = static_cast<char>(N);尝试这样做但它不会工作，而是打印不是（a-z）的字符图像如何将数字打印成字母？

#include  <cstdlib>
#include  <iostream>
using namespace std;

// Function getUserInput obtains an integer input value from the user.
//  This function performs no error checking of user input.
int getUserInput()
{
    int N(0);

    cout << endl << "Please enter a positive, odd integer value, between (1-51): ";
    cin >> N;
    if (N < 1 || N > 51 || N % 2 == 0)
    {
        cout << "Error value is invalid!" << "\n";
        cout << endl << "Please enter a positive, odd integer value, between (1-51): ";
        cin >> N;
        system("cls");
    }

    cout << endl;
    return N;
} // end getUserInput function

//  Function printDiamond prints a diamond comprised of N rows of asterisks.
//  This function assumes that N is a positive, odd integer.
void printHourglass(int N)
{
    char c = static_cast<char>(N);
    for (int row = (N / 2); row >= 1; row--)
    {
        for (int spaceCount = 1; spaceCount <= (N / 2 + 1 - row); spaceCount++)
            cout << ' ';
        for (int column = 1; column <= (2 * row - 1); column++)
            cout << c;
        cout << endl;
    } // end for loop
    // print top ~half of the diamond ...
    for (int row = 1; row <= (N / 2 + 1); row++)
    {
        for (int spaceCount = 1; spaceCount <= (N / 2 + 1 - row); spaceCount++)
            cout << ' ';
        for (int column = 1; column <= (2 * row - 1); column++)
            cout << c;
        cout << endl;
    } // end for loop

    // print bottom ~half of the diamond ...


    return;
} // end printDiamond function

int main()
{
    int N = 1;

    while (N == 1)
    {
        printHourglass(getUserInput());
        cout << endl;
        cout << "Would you like to print another hourglass? ( 1 = Yes, 0 = No ):";
        cin >> N;
    }
} // end main function

Answer 1

C函数，itoa
C ++，使用stringstream
升压:: lexical_cast的

实际上，对于您的情况，您可以直接将其打印出来。 cout << N

Answer 2

这些字母的编号不是A，而是1或类似的东西。您可能使用的是ASCII / UTF-8系统。因此，在printHourglass中，将cout << N替换为

cout << static_cast<char>('A' + count - 1);

将整数转换为字符

2 个答案: