我使用递归来编写一个类的程序,以模仿某些简单的分支结构,如树。在我向教授展示之前,我认为我的代码很棒。他说我的代码太复杂了,并说我需要简化它。除了将它们分开外,我不确定我还能做些什么。有小费吗? (我是一个初学者,所以对我很容易。)这个程序创建了多个不同厚度,分支数量和不同坐标的树。
import random
import turtle
##I'm using a python module called turtle to visualize results
p1 = turtle.Pen()
##Creates a pen
p1.tracer(True)
## Shows pen drawing
p1.up()
p1.left(90)
d=random.randint(0,2)
## Varying thickness of branch
length=150
##Length of branches
contract=random.uniform(.5,1)
## Varying degree of contraction
branch=random.randint(5,8)
## Varying amount of branches
first=random.randint(30,70)
## Varying first degree of branch
next=random.randint(1,30)
## Varying degree between each branches
number1=random.randint(10,20)
number2=random.randint(-100,100)
number3=random.randint(-100,100)
# Range of numbers used for coordinates
def drawFern1(pen, depth, length, contractBy, branches, firstBranchAngle, nextBranchAngle):
if depth > 0:
#Pen's Position and heading
heading = pen.heading()
position = pen.position()
pen.width(depth)
pen.forward(length)
pen.left(firstBranchAngle)
for i in range(branches):
drawFern1(pen, depth-1, contractBy*length, contractBy,branches,firstBranchAngle,nextBranchAngle)
pen.right(nextBranchAngle)
pen.setheading(heading)
pen.setposition(position)
# Ensures that multiple trees are created each at different coordinates.
for i in range(number1):
p1.sety(number2)
p1.setx(number3)
p1.down()
drawFern1(p1,d,length,contract,branch,first,next)
number2 = random.randint(-100,100)
number3 = random.randint(-100,100)
p1.up()
答案 0 :(得分:0)
这段代码对我来说非常可靠,特别是对于Python初学者。我看到的情况要糟糕得多。
如果我正在编写它,我想我只在主number2
循环内计算number3
和for
- 这里的启动定义通常很方便{ {1}}循环,但在这种情况下不是必需的。我还会尝试使用更多解释性变量名,并且根据问题陈述,我可能要求随机生成的while
值至少为1 - 如果depth
生成为0,则不会绘制任何内容
我的版本看起来像这样:
depth
除了将x和y坐标随机化移动到主循环中,在文件前面移动递归函数定义,并使用一些更明确的变量名称之外,我还使用import random
import turtle
def drawFern(pen, depth, length, contraction, branches, firstBranchAngle, nextBranchAngle):
if depth > 0:
# Pen's Position and heading
heading = pen.heading()
position = pen.position()
pen.width(depth)
pen.forward(length)
pen.left(firstBranchAngle)
for i in xrange(branches):
drawFern(pen, depth-1, contraction*length, contraction, branches, firstBranchAngle, nextBranchAngle)
pen.right(nextBranchAngle)
pen.setheading(heading)
pen.setposition(position)
# I'm using a python module called turtle to visualize results
# Creates a pen
pen = turtle.Pen()
# Shows pen drawing
pen.tracer(True)
pen.up()
pen.left(90)
# Configure initial state
# Varying depth of recursive fern
depth = random.randint(1,2)
# Length of branches
length = 150
# Varying degree of contraction
contraction = random.uniform(.5,1)
# Varying number of branches
branches = random.randint(5,8)
# Varying first degree of branch
first_angle = random.randint(30,70)
# Varying degree between each branches
next_angle = random.randint(1,30)
number_of_trees =random.randint(10,20)
for i in xrange(number_of_trees):
new_x = random.randint(-100, 100)
new_y = random.randint(-100, 100)
pen.setx(new_x)
pen.sety(new_y)
pen.down()
drawFern(pen, depth, length, contraction, branches, first_angle, next_angle)
pen.up()
调用而不是{{ 1}}调用 - 如果你使用的是Python 2.x,那就是一个简单的优化。如果您使用的是Python 3,xrange
是正确的。但这些都是微小的变化。
你也可以在range
循环之前输入一个range
子句甚至不尝试if
等于1 - 这是另一个小优化,尽管不会产生很大的差异
答案 1 :(得分:0)
在我向教授展示之前,我认为自己的代码很棒。他告诉我 代码太复杂了,说我需要简化它。
考虑到绘制的树的质量,这是相当复杂的代码:
仅绘制垂直线和空白屏幕在编写的程序随机参数内!让我们重新设计该程序,将一些随机性从静态配置代码移到递归例程本身中。我们还将微调随机范围并清理代码,主要是通过消除仅设置和使用一次的变量:
from random import randint, uniform
from turtle import Screen, Pen # Using python turtle module to visualize results
# Configure initial state
DEPTH = randint(3, 4) # Varying thickness and splitting of branches
LENGTH = randint(125, 150) # Length of branches
CONTRACT_BY = uniform(0.4, 0.8) # Varying degree of contraction
def drawFern(pen, depth, length, contractBy):
if depth < 1:
return
# Save pen's position and heading
heading = pen.heading()
position = pen.position()
pen.width(depth * 1.5) # pen thickness depends on branching
pen.forward(length)
pen.left(randint(30, 70)) # Varying first degree of branch)
for _ in range(randint(5, 8)): # Varying amount of branches
drawFern(pen, depth - 1, contractBy * length, contractBy)
pen.right(randint(5, 30)) # Varying degree between each branches
# Restore pen's Position and heading
pen.setheading(heading)
pen.setposition(position)
screen = Screen()
pen = Pen(visible=False)
pen.left(90)
screen.tracer(False)
# Ensure that multiple trees are created each at different coordinates.
for i in range(randint(10, 20)):
pen.penup()
pen.setposition(randint(-200, 200), randint(-300, 0))
pen.pendown()
drawFern(pen, DEPTH, LENGTH, CONTRACT_BY)
screen.tracer(True)
screen.mainloop()