Question

以下是一个代码，用于查看不同数据类型在内存中的存储方式。

#include <stdio.h>

void newline(void)
{
    putchar('\n');
}

void showbyte(char *string, int len)
{
    int i;
    for (i = 0; i < len; i++)
    printf("%p\t0x%.2x\n", string+i, *(string+i));
}

int main()
{
    int i = 12345;
    float f = 1234.5;
    double d = 1234.5;
    char name[] = "12345";
    showbyte((char *)&i, sizeof i);
    newline();
    showbyte((char *)&f, sizeof f);
    newline();
    showbyte((char *)&d, sizeof d);
    newline();
    showbyte((char *)&name, sizeof name);
    return 0;
}

输出

0x7fff8a9ab2cc  0x39
0x7fff8a9ab2cd  0x30
0x7fff8a9ab2ce  0x00
0x7fff8a9ab2cf  0x00

0x7fff8a9ab2c8  0x00
0x7fff8a9ab2c9  0x50
0x7fff8a9ab2ca  0xffffff9a
0x7fff8a9ab2cb  0x44

0x7fff8a9ab2c0  0x00
0x7fff8a9ab2c1  0x00
0x7fff8a9ab2c2  0x00
0x7fff8a9ab2c3  0x00
0x7fff8a9ab2c4  0x00
0x7fff8a9ab2c5  0x4a
0x7fff8a9ab2c6  0xffffff93
0x7fff8a9ab2c7  0x40

0x7fff8a9ab2b0  0x31
0x7fff8a9ab2b1  0x32
0x7fff8a9ab2b2  0x33
0x7fff8a9ab2b3  0x34
0x7fff8a9ab2b4  0x35
0x7fff8a9ab2b5  0x00

float 1234.5的IEEE-754表示为0x449a5000，double 1234.5的{-1}为0x40934A0000000000。在打印float和double变量内容时，它会显示4-byte个内容。

即 0x7fff8a9ab2ca 0xffffff9a和 0x7fff8a9ab2c6 0xffffff93。

但是每个内存位置只能存储1-byte个数据，那么为什么会这样呢？

Answer 1

在这种情况下，

未签名是您的朋友，因为char is by default a signed type

如果您将某些类型从 char 更改为 unsigned char ，则会得到正确的结果：

#include <stdio.h>

void newline(void)
{
    putchar('\n');
}

void showbyte(unsigned char *string, int len)
{
    int i;
    for (i = 0; i < len; i++)
      printf("%p\t0x%.2x\n", string+i, *(string+i));
}

int main()
{
    int i = 12345;
    float f = 1234.5;
    double d = 1234.5;
    char name[] = "12345";
    showbyte((unsigned char *)&i, sizeof i);
    newline();
    showbyte((unsigned char *)&f, sizeof f);
    newline();
    showbyte((unsigned char *)&d, sizeof d);
    newline();
    showbyte((unsigned char *)&name, sizeof name);
    return 0;
}

在这种情况下，你得到：

0x7fff5d5a98b8  0x39
0x7fff5d5a98b9  0x30
0x7fff5d5a98ba  0x00
0x7fff5d5a98bb  0x00

0x7fff5d5a98b4  0x00
0x7fff5d5a98b5  0x50
0x7fff5d5a98b6  0x9a
0x7fff5d5a98b7  0x44

0x7fff5d5a98a8  0x00
0x7fff5d5a98a9  0x00
0x7fff5d5a98aa  0x00
0x7fff5d5a98ab  0x00
0x7fff5d5a98ac  0x00
0x7fff5d5a98ad  0x4a
0x7fff5d5a98ae  0x93
0x7fff5d5a98af  0x40

0x7fff5d5a98a2  0x31
0x7fff5d5a98a3  0x32
0x7fff5d5a98a4  0x33
0x7fff5d5a98a5  0x34
0x7fff5d5a98a6  0x35
0x7fff5d5a98a7  0x00

访问连续存储位置时出现打印错误

1 个答案: