Question

我试图将长值传递给函数。但是它说“令牌上的语法错误”很长“，删除此令牌”。请解释一下这是什么以及何时出现这种错误发生了

代码

public static void main(String[] args) {

    Calendar currenttime = Calendar.getInstance();          
    Date date = currenttime.getTime();
    long timeInMillisSinceEpoch = date.getTime(); 
    long ctimeInMinutesSinceEpoch = timeInMillisSinceEpoch / 1000;              
    Calendar subhr = Calendar.getInstance();
    subhr.add(Calendar.HOUR, -1);              
    Date date1 = subhr.getTime();
    long timeInMillisSinceEpoch1 = date1.getTime(); 
    long btimeInMinutesSinceEpoch1 = timeInMillisSinceEpoch1 / 1000;
    //error on this line 
    printCSV(long btimeInMinutesSinceEpoch1,long ctimeInMinutesSinceEpoch); 
}

public static void printCSV(long bdata,long cdata) {
    try {
        URL url = new URL(protocol + "://" + hostname + "/apiv2/csv.xml?username=" + userName + "&password=" + password + "&form_id=" + formId + "&begin_second="+bdata +"&end_second="+cdata);
        HttpURLConnection urlCon = (HttpURLConnection) url.openConnection();
        System.out.println(urlCon);
    }

请帮助我。

Answer 1

将printCSV(long btimeInMinutesSinceEpoch1,long ctimeInMinutesSinceEpoch);更改为

printCSV(btimeInMinutesSinceEpoch1,ctimeInMinutesSinceEpoch);

在将参数传递给函数时，不需要在函数调用中指定输入参数的数据类型。

Answer 2

就是这一行：

    //error on this line 
    printCSV(btimeInMinutesSinceEpoch1, ctimeInMinutesSinceEpoch);

Answer 3

在调用方法时，您无需指定输入参数的类型。因此改变这个：

printCSV(long btimeInMinutesSinceEpoch1,long ctimeInMinutesSinceEpoch);

到

printCSV(btimeInMinutesSinceEpoch1,ctimeInMinutesSinceEpoch);

Answer 4

使用：

printCSV(btimeInMinutesSinceEpoch1, ctimeInMinutesSinceEpoch);

没有long。

Answer 5

   long btimeInMinutesSinceEpoch1 = timeInMillisSinceEpoch1 / 1000;
    long ctimeInMinutesSinceEpoch = timeInMillisSinceEpoch / 1000;

在上面的两行中，您已将btimeInMinutesSinceEpoch1和ctimeInMinutesSinceEpoch声明为长字型。现在这一行printCSV(long btimeInMinutesSinceEpoch1,long ctimeInMinutesSinceEpoch); 你再次宣布同样的事情正确答案 printCSV(btimeInMinutesSinceEpoch1,ctimeInMinutesSinceEpoch);

如何解决令牌上的语法错误

5 个答案: