Django GenericForeignKey:两个模型具有相同的related_name时的访问器冲突

时间:2013-10-14 10:23:12

标签: python django django-models foreign-keys generic-foreign-key

当我syncdb时,我会收到很多这样的错误:

   transcription.transcription1: Accessor for field 'participant_content_type' clashes with related field 'ContentType.auxi
    liary_model_as_participant'. Add a related_name argument to the definition for 'participant_content_type'.
    transcription.transcription1: Reverse query name for field 'participant_content_type' clashes with related field 'Conten
    tType.auxiliary_model_as_participant'. Add a related_name argument to the definition for 'participant_content_type'.

我的模型已经有相关名称:

# my base class which I intend to inherit from in many places.
# Many types of AuxiliaryModel will point at participant/match objects.:
class AuxiliaryModel(models.Model):
    participant_content_type = models.ForeignKey(ContentType,
                                                 editable=False,
                                                 related_name = 'auxiliary_model_as_participant')
    participant_object_id = models.PositiveIntegerField(editable=False)
    participant = generic.GenericForeignKey('participant_content_type',
                                            'participant_object_id',
                                            )

    match_content_type = models.ForeignKey(ContentType,
                                           editable=False,
                                           related_name = 'auxiliary_model_as_match')
    match_object_id = models.PositiveIntegerField(editable=False)
    match = generic.GenericForeignKey('match_content_type',
                                      'match_object_id',
                                      )

    class Meta:
        abstract = True


class Transcription(AuxiliaryModel):

    transcription = models.TextField(max_length=TRANSCRIPTION_MAX_LENGTH,
                                        null=True)

    class Meta:
        abstract = True

class Transcription1(Transcription):
    pass

class Transcription2(Transcription):
    pass

class Transcription3(Transcription):
    pass

当我发表评论Transcription2Transcription3时问题就消失了,所以看起来像related_names冲突。我必须让它们与众不同吗?如果是这样,有没有办法在不必在每个子类中编写样板代码的情况下执行此操作?

1 个答案:

答案 0 :(得分:2)

来自Django文档https://docs.djangoproject.com/en/dev/topics/db/models/#be-careful-with-related-name

  

如果在ForeignKey或ManyToManyField上使用related_name属性,则必须始终为该字段指定唯一的反向名称。这通常会导致抽象基类出现问题,因为此类中的字段包含在每个子类中,每次都具有完全相同的属性值(包括related_name)。

     

要解决此问题,当您在抽象基类(仅)中使用related_name时,名称的一部分应包含'%(app_label)s'和'%(class)s'。

在这种情况下,我认为这将有效:

    participant_content_type = models.ForeignKey(ContentType,
                                             editable=False,
                                             related_name = '%(app_label)s_%(class)s_as_participant')
    match_content_type = models.ForeignKey(ContentType,
                                       editable=False,
                                       related_name = '%(app_label)s_%(class)s_model_as_match')

因此,使用%(app_label)_transcription2_as_participant,您可以访问Transcription2.participant_content_type的反向

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