Question

我正在尝试创建一个可以通过youtube网址下载mp3文件的应用。

我对youtube-mp3.org api进行了一些研究，这是我认为应该这样做的方式：

获取http://www.youtube-mp3.org/api/pushItem/?item=http://www.youtube.com/watch?v=xo9EV3A4oaA&xy=yx
步骤1返回一个ID，您必须在以下请求中使用该ID："http://www.youtube-mp3.org/api/itemInfo/?video_id=" + ID
第2步返回另一个代码，您必须在此请求中使用该代码："http://www.youtube-mp3.org/get?video_id=xo9EV3A4oaA&h=" + <code from step 2>
第3步重演mp3。

不幸的是，我的代码在第1步已失败：我收到404，找不到页面。

这是我的代码（仅适用于第1步）：

private DefaultHttpClient createHttpClient() {
    HttpParams my_httpParams = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(my_httpParams, 3000);
    HttpConnectionParams.setSoTimeout(my_httpParams, 15000);
    SchemeRegistry registry = new SchemeRegistry();
    registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
    ThreadSafeClientConnManager multiThreadedConnectionManager = new ThreadSafeClientConnManager(my_httpParams, registry);
    DefaultHttpClient httpclient = new DefaultHttpClient(multiThreadedConnectionManager, my_httpParams);
    return httpclient;
}

private class DownloadVid extends AsyncTask<Void, Void, Void> {

    int mStatusCode = 0;
    String content = "";

    @Override
    protected Void doInBackground(Void... args) {

        String url = "http://www.youtube-mp3.org/api/pushItem/?item=http://www.youtube.com/watch?v=xo9EV3A4oaA&xy=yx";

        DefaultHttpClient httpclient = createHttpClient();
        HttpGet httpget = new HttpGet(url);
        httpget.addHeader("Accept-Location", "*");

        try {
            HttpResponse response = httpclient.execute(httpget);
            StatusLine statusLine = response.getStatusLine();
            mStatusCode = statusLine.getStatusCode();

            if (mStatusCode == 200){
                content = EntityUtils.toString(response.getEntity());
            }

        } catch (ClientProtocolException e) {
            e.printStackTrace();
            mStatusCode = 0;
        } catch (IOException e) {
            e.printStackTrace();
            mStatusCode = 0;
        } catch (IllegalStateException e){
            e.printStackTrace();
            mStatusCode = 0;
        }

        return null;
    }

    @Override
    protected void onPostExecute(Void arg) {

        mProgressDialog.dismiss();

        Toast.makeText(MainActivity.this, "Result=" + content + " StatusCode=" + mStatusCode, Toast.LENGTH_LONG).show();
    }
}

我不确定为什么它不起作用。有什么想法吗？

Answer 1

对项目参数进行编码，如下所示：

String item = URLEncoder.encode("http://www.youtube.com/watch?v=xo9EV3A4oaA", "utf-8");
String url = "http://www.youtube-mp3.org/a/pushItem/?item="+item+"&xy=yx";

或者像这样：

Uri uri = new Uri.Builder()
    .scheme("http")
    .authority("www.youtube-mp3.org")
    .path("/a/pushItem/")
    .appendQueryParameter("item", "http://www.youtube.com/watch?v=xo9EV3A4oaA")
    .appendQueryParameter("xy", "yx")
    .build();

404与youtube-mp3.org api

1 个答案: