Question

我想要一些输入，如何从我的代码中的表单执行更新查询我相信我在错误的地方我没有得到任何错误但它没有更新我相信它在哪里它在代码？我想我需要一个循环来捕获文本框的更新..正确吗？我有更好的方式来看待这个吗？我打算将更新发送到新页面但是认为将它保存在一个页面中会更好，这样您就可以看到我在哪里提交了代码。 phpmyadmin如何更新文本框？我假设他们使用java脚本会更好吗？任何建设性的意见将不胜感激。

            <html>
            <?php
            session_start();
            ?>
            <head>

            <basefont face="Arial">
            <title>Search</title>
            </head>

            <body>
                  <?php

            // include the page Header

            include('header.php');

            ?>

            <?php
            $today = date("n/j/Y");

             // set database server access variables:

            $host = "localhost";
            $user = "test";
            $pass = "test";
            $db = "test";

            // open connection

            $connection = mysqli_connect($host, $user, $pass, $db); 
            if (mysqli_connect_errno($connection)) {
                echo "Failed to connect to MySQL: " . mysqli_connect_error();
            }
            // create query
            $query = "SELECT * FROM testingqa1160";
            $result = mysqli_query($connection, $query);

            $subbox = '<input type="Submit" value="Update" name="Submit">';
             // echo '<form name="release" action="somepage.php" method="get">';
            if (mysqli_num_rows($result) > 0) {

                // print them one after another
                echo "<center>"; 
                echo "<center><FONT SIZE=18>";
                echo "   Material  to be tested  </font>";
                echo "</center>";


                echo "<center><table cellpadding=1 border=1>";
                   //echo "<tr>";
                    echo "<center>";
                    echo "<td><center>"."ID"."</center></td>";
                    echo "<td><center>"."Material"."</center></td>";
                    echo "<td><center>"."Test"."</center></td>";
                    echo "<td><center>"."Sample"."</center></td>";
                    echo "<td><center>"."Freq"."</center></td>";
                    echo "<td><center>"."STP"."</center></td>";
                    echo "<td><center>"."Release"."</center></td>";
                    echo "<td><center>"."Notes"."</center></td>";
                    echo "<td><center>"."LSL"."</center></td>";
                    echo "<td><center>"."USL"."</center></td>";
                    echo "<td><center>"."Lot"."</center></td>";
                    echo "<td><center>"."Results"."</center></td>";
                    echo "<td><center>"."Release"."</center></td>";
                    echo "<td><center>"."Date"."</center></td>";
                    echo "</center></tr>";

                while($row = mysqli_fetch_row($result)) {

                    echo "<tr>";
                    $lottxtbox ='<input type="text" name="'.$row[0].'lotbox"size="6" value="'.$row[11].'">';
                    $restxtbox ='<input type="text" name="'.$row[0].'resbox" size="4" value="'.$row[12].'">';
                    $chbox = '<input type="checkbox" name="'.$row[0].'checkbox">';

                    echo "<td>".$row[0]."</td>";
                    // echo "<td>".$row[1]."</td>";
                    echo "<td><center>".$row[2]."</center></td>";
                    echo "<td><center>".$row[3]."</center></td>";
                    echo "<td><center>".$row[4]."</center></td>";
                    echo "<td><center>".$row[5]."</center></td>";
                    echo "<td><center>".$row[6]."</center></td>";
                    echo "<td><center>".$row[7]."</center></td>";
                    echo "<td><center>".$row[8]."</center></td>";
                    echo "<td><center>".$row[10]."</center></td>";
                    echo "<td><center>".$row[9]."</center></td>";
                    echo "<td><center>".$lottxtbox."</center></td>";
                    echo "<td><center>".$restxtbox."</center></td>";
                    echo "<td><center>".$chbox."</center></td>";
                    echo "<td>".$today."</td>";
                    // echo "<td>".$row[12]."</td>";
                    // echo "<td>".$row[13]."</td>";
                            echo "</tr>";

                }

                echo "</table></center>";


            echo "</center>";
            echo "<td><center>".$subbox."</center></td>";
            echo "</form>";



            }

            else {

                // no

                // print status message
            echo "<center><FONT SIZE=18>";
            echo $_GET["mnumber"];
                echo "   Material is not found! </font>";
                echo "</center>";

            }

            // free result set memory

            mysqli_free_result($result);

            // close connection

            mysqli_close($connection);
            ?>

            <?php
            if(isset($_POST['Submit'])){//if the submit button is clicked
            $update = $_POST['.$row[0]."lotbox"'];
            $query="UPDATE Lot = $update where trace = '".$row[0]."'";
            mysqli_query($connection,$query);
            }
            ?>

                  <?php

            // include the page footer

            include('footer.php');

            ?>
            </body>

            </html>

Answer 1

您正在关闭连接但之后仍然使用更新查询+您的更新查询错误。请查看此更新查询（您忘记了SET：

update query

UPDATE table_name
SET column1=value, column2=value2,...
WHERE some_column=some_value

你为什么要这样做？：

            mysqli_close($connection);
        ?>

        <?php
        if(isset($_POST['Submit'])){//if the submit button is clicked

关闭PHP标记并立即再次打开它。为什么呢？

从表单更新SQL

1 个答案: