我使用分页脚本查看搜索结果， 但是当我点击下一页时打破了结果，因为没有在另一页上传递变量。
我在页面“index.php”中创建搜索表单。 和“search.php”查看结果。
请修改我的代码!!! 非常感谢
（抱歉坏的坏英语（我不使用翻译））
“的index.php”
<div id="main" style="width: 1024px; margin: 0 auto; background: #eee;border: solid 1px #000">
<img style="margin:30px 300px;" alt="logoAifa" src="https://www.agenziafarmaco.gov.it/areariservata/sites/all/themes/genesis/genesis_AIFA/img/logo.png"/>
<a style="font-family: Times;font-size: 24px; font-weight: bold; margin: 30px 390px">Asset Management</a>
<form style="margin: 30px 30px 30px 30px" method="get" action="php/search.php">
<table>
<tr>
<td><input type="text" placeholder="Cerca" name="cerca"></td><td><input type="submit" value="go"></td>
<td><a style="font-family: Times;font-size:14px;color: blue;text-decoration: underline;">Ricerca Avanzata</a></td>
</tr>
</table>
</form>
<div id="db">
<?php
include('php/conn.php');
session_start();
etc...
“的search.php”
<?php
include('conn.php');
session_start();
$cerca = $_REQUEST['cerca'];
$_SESSION['cerca'] = $cerca;
$cerca = mysql_escape_string(stripslashes($cerca));
$tableName="asset";
$targetpage = "search.php";
$limit = 50;
$query = "SELECT COUNT(*) as num FROM $tableName WHERE Nome LIKE '%$cerca%' OR Cognome LIKE '%$cerca%' OR Utilizzo LIKE '%$cerca%' OR IDAIFA LIKE '%$cerca%' OR Tipologia LIKE '%$cerca%' OR Modello LIKE '%$cerca%' OR Stato LIKE '%$cerca%' ";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages['num'];
$stages = 3;
$page = isset($_GET['page']) ? mysql_real_escape_string($_GET['page']) : 0;
if($page){
$start = ($page - 1) * $limit;
}else{
$start = 0;
}
// Get page data
$query1 = "SELECT * FROM $tableName WHERE Nome LIKE '%$cerca%' OR Cognome LIKE '%$cerca%' OR Utilizzo LIKE '%$cerca%' OR IDAIFA LIKE '%$cerca%' OR Tipologia LIKE '%$cerca%' OR Modello LIKE '%$cerca%' OR Stato LIKE '%$cerca%' LIMIT $start, $limit ";
$result = mysql_query($query1);
// Initial page num setup
if ($page == 0){$page = 1;}
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$LastPagem1 = $lastpage - 1;
$paginate = '';
if($lastpage > 1)
{
$paginate .= "<div class='paginate'>";
// Previous
if ($page > 1){
$paginate.= "<a href='$targetpage?page=$prev'>previous</a>";
}else{
$paginate.= "<span class='disabled'>previous</span>"; }
// Pages
if ($lastpage < 7 + ($stages * 2))
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
elseif($lastpage > 5 + ($stages * 2))
{
if($page < 1 + ($stages * 2))
{
for ($counter = 1; $counter < 4 + ($stages * 2); $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
elseif($lastpage - ($stages * 2) > $page && $page > ($stages * 2))
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $page - $stages; $counter <= $page + $stages; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}
else
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $lastpage - (2 + ($stages * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page){
$paginate.= "<span class='current'>$counter</span>";
}else{
$paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
}
// Next
if ($page < $counter - 1){
$paginate.= "<a href='$targetpage?page=$next'>next</a>";
}else{
$paginate.= "<span class='disabled'>next</span>";
}
$paginate.= "</div>";
}
echo $total_pages.' Results';
// pagination
?>
<?php
echo "<table border='1' style='margin:0 auto;'>";
echo "<tr>",
"<td colspan='3'> Azioni </td> <td> Nome </td> <td> Cognome </td> <td> IDAIFA </td> <td> Utilizzo</td> <td> Tipologia</td> <td>Marca</td> <td>Modello</td> <td>Stato</td>",
"</tr> \n";
while($dati = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td> <a href='detailasset.php?ID=$dati[ID]'><img src='../images/eye.png'></a> </td>";
echo "<td> <a href='modasset.php?ID=$dati[ID]'><img src='../images/edit.png'></a> </a> </td>";
echo "<td> <a href='deleteasset.php?ID=$dati[ID]?confirm=true' class='confirm'> <img src='../images/delete.png'></a></td>";
print "<td> $dati[Nome] </td>";
print "<td> $dati[Cognome] </td>";
print "<td> $dati[IDAIFA] </td>";
print "<td> $dati[Utilizzo] </td>";
print "<td> $dati[Tipologia] </td>";
print "<td> $dati[Marca] </td>";
print "<td> $dati[Modello] </td>";
print "<td> $dati[Stato] </td>";
echo "</tr> \n";
}
echo "</table></div>\n";
echo $paginate;
?>
</div>
答案 0 :(得分：1)
我认为您要说的是搜索字词没有正确传递？
从我在代码中看到的内容，变量$cerca是搜索词。
您可以使用$_GET['cerca']代替$_REQUEST
另外更重要的是，我不认为你可以在查询中这样做：
$query = "SELECT COUNT(*) as num FROM $tableName WHERE Nome LIKE '%$cerca%'
您应该拆分LIKE部分，例如此
$query = "SELECT COUNT(*) as num FROM $tableName WHERE Nome LIKE '%" . $cerca . "%'
在你做LIKE
或者我认为这就是你所要求的......