地理位置经典的asp json响应

时间:2013-10-15 21:30:22

标签: json asp-classic geolocation

我正在尝试解析来自google maps geolocation api的json响应。我用这段代码得到了一个json响应:

     set xmlHTTP = server.createobject("MSXML2.ServerXMLHTTP.6.0")
     xmlHTTP.open "GET", "https://maps.googleapis.com/maps/api/distancematrix/json?origins=50.9255685,29.2703104&destinations=46.446251,28.570993&mode=driving&language=sv-SE&sensor=false", false
     xmlHTTP.send()
     LatLongFeed = xmlHTTP.ResponseText

我试图获取街道地址的值(来源和目的地,我试图找到距离,但我无法让它工作。

如何获取响应中的值,以便在经典的asp代码中使用它?

2 个答案:

答案 0 :(得分:0)

我尝试过不同类型的解决方案,这是基于JSON类(http://www.aspjson.com/

Set oJSON = New aspJSON

'Load JSON string
oJSON.loadJSON("https://maps.googleapis.com/maps/api/distancematrix/json?origins=" & rs("LatiStart")& "," & rs("LongStart")& "&destinations=" & rs("LatiStop")& "," & rs("LongStop")& "&mode=driving&language=sv-SE&sensor=false")

'Get single value
Response.Write oJSON.data("distance") & "<br>"

'Loop through collection
For Each subItem In oJSON.data("distance")
    Response.Write subItem & ": " & _
    oJSON.data("distance").item(subItem) & "<br>"
Next

'Return the object
Response.Write oJSON.JSONoutput()

跑步时我得到了 LineNumber 55 ErrorCode 800a01c3 说明对象不是集合

第55行是(对于每个子项目在oJSON.data(“距离”))

我的示例中的json响应基于示例坐标,并且不是实际位置。地址仅包含标准的a-z。

答案 1 :(得分:0)

加载JSON不起作用。您应该在那里加载对googleapis的通话响应,而不是请求网址。 所以像这样:

URL = "https://maps.googleapis.com/maps/api/distancematrix/json?origins=" & rs("LatiStart")& "," & rs("LongStart")& "&destinations=" & rs("LatiStop")& "," & rs("LongStop")& "&mode=driving&language=sv-SE&sensor=false"
Set objXmlHTTP = CreateObject("MSXML2.ServerXMLHTTP.6.0")
objXmlHTTP.Open "POST", URL, False
objXmlHTTP.setRequestHeader "Content-Type", "application/json"

objXmlHttp.Send
Set oJSON = New aspJSON
oJSON.loadJSON(objXmlHTTP.ResponseText)
相关问题