Question

我正在尝试执行INSERT INTO SELECT语句，并在SELECT中嵌入了另一个INSERT。原因是我需要复制一个外键并在外部插入中使用新的行id。像这样：

INSERT INTO Contracts ( 
  JobId, 
  InvoiceNumber
  ExpensesId)
SELECT 
  j.Id,
  j.InvoiceNumber, 
  (INSERT INTO Expenses (Bus, Toll) SELECT Bus, Toll FROM Expenses WHERE Id = j.ExpensesId)
FROM Jobs j

这个SQL没有运行，因为INSERT没有返回任何内容，但有没有办法做到这一点，或者更好的方法？

Answer 1

你不能那样做。

我认为这可能是你想要做的事情？

INSERT INTO Contracts ( 
  JobId, 
  InvoiceNumber
  ExpensesId)
SELECT 
  j.Id,
  j.InvoiceNumber, 
  j.ExpensesID
FROM Expenses 
   INNER JOIN Jobs j ON expenses.Id = j.ExpensesId

如果您需要复制费用行，则需要先执行此操作，然后使用SCOPE_IDENTITY获取新ID。

declare @expenseid int = -- your expense ID
declare @newid int

INSERT Expenses (Bus, Toll)
SELECT Bus, Toll FROM Expenses WHERE Id = @expenseID
SELECT @newID = SCOPE_IDENTITY()

INSERT INTO Contracts ( 
  JobId, 
  InvoiceNumber
  ExpensesId)
SELECT 
  j.Id,
  j.InvoiceNumber, 
  @newID
FROM Expenses 
WHERE Id = @expenseID

如果你想做批次

DECLARE @inserts table(expenseid int, jobid int)

INSERT Expenses (Bus, Toll)
OUTPUT inserted.id, Jobs.ID INTO @inserts
SELECT Bus, Toll FROM Expenses 
       INNER JOIN Jobs ON Jobs.ExpenseID = Expenses.ID

INSERT Contracts (JobID, InvoiceNumber, ExpensesID)
SELECT j.ID, j.InvoiceNumber, i.ExpenseID
FROM Jobs j
     INNER JOIN @inserts I on j.ID = i.jobid

......或类似的东西 - 不太确定我是否能够完全理解您的数据结构。

Answer 2

您无法在select语句中编写insert。它不返回列字段或对象

插入INSERT INTO SELECT中的INSERT

2 个答案: