Question

打印时，我有NSURL看起来像这样 控制台：

<AVURLAsset: 0x170232800, URL = assets-library://asset/asset.MOV?id=426C5913-86CF-4476-2DB6-6A9AAC626AF4&ext=MOV>

获取此网址的ID部分的正确方法是什么？目标是使用426C5913-86CF-4476-2DB6-6A9AAC626AF4字符串。

Answer 1

您可以使用以下内容：

NSURL *url = [[NSURL alloc] initWithString:@"assets-library://asset/asset.MOV?id=426C5913-86CF-4476-2DB6-6A9AAC626AF4&ext=MOV"];
NSArray *components = [[url query] componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@"=&"]];
NSMutableDictionary *params = [NSMutableDictionary dictionary];
for (NSUInteger idx = 1; idx < components.count; idx+=2) {
    params[components[idx - 1]] = components[idx];
}

NSLog(@"params[@id] = %@", params[@"id"]);

为此目的创建一个NSURL类别是个好主意。

Answer 2

开始于：

NSURL *urlAddress = [NSURL URLWithString:yourAddressString];

然后：

[urlAddress scheme] gives the Scheme;
[urlAddress host] gives the host
[urlAddress path], [urlAddress relativePath], [urlAddress query], [urlAddress fragment] or [urlAddress parameterString] gives the correspondent parts of your urlAddress

如何获得此NSURL的ID部分？

2 个答案: