需要解释Python中的while循环

时间:2013-10-20 18:59:48

标签: python while-loop

我是Python的初学者,我一直在练习。书中有一款名为Word Jumple的游戏。这是我需要做的: 改进“Word Jumble”,使每个单词与提示配对。 玩家应该能够看到他或她被卡住的提示。 添加一个评分系统,奖励那些在没有提示的情况下解决混乱问题的玩家。

这就是我所做的:

# Word Jumble
#
# The computer picks a random word and then "jumbles" it
# The player has to guess the original word
import random

# create a sequence of words to choose from
WORDS = ("python", "jumble", "easy", "difficult", "answer", "xylophone")

# pick one word randomly from the sequence
word = random.choice(WORDS)

# create a variable to use later to see if the guess is correct
correct = word

# create a jumbled version of the word
jumble =""
hint = "False"

while word:
    position = random.randrange(len(word))
    jumble += word[position]
    word = word[:position] + word[(position + 1):]

# start the game
print(
"""
Welcome to Word Jumble!
Unscramble the letters to make a word.
(Press the enter key at the prompt to quit.)
"""
)
print("The jumble is:", jumble)

guess = input("\nYour guess: ")
while guess != correct and guess != "":
    if guess == "hint" and word == "python":
        hint = "True"
        print("It's a snake")
        guess = input("Your guess: ")
    elif guess == "hint" and word == "jumble":
        hint = "True"
        print("It's a game")
        guess = input("Your guess: ")
    elif guess == "hint" and word == "easy":
        hint = "True"
        print("It's type of difficulty")
        guess = input("Your guess: ")
    elif guess == "hint" and word == "difficulty":
        hint = "True"
        print("It's type of difficulty")
        guess = input("Your guess: ")
    elif guess == "hint" and word == "answer":
        hint = "True"
        print("It's the opposite of question")
        guess = input("Your guess: ")
    elif guess == "hint" and word == "xylophone":
        hint = "True"
        print("Don't know WTF is that")
        guess = input("Your guess: ")
    else:
        print("Sorry, that's not it.")
        guess = input("Your guess: ")

if guess == correct:
    print("That's it! You guessed it!\n")

if hint == "False":
    print("Great! You did it without a hint")
else:
    print("Dat hint, man")

print("Thanks for playing.")
input("\n\nPress the enter key to exit.")

结果我有了这个:

Welcome to Word Jumble!
Unscramble the letters to make a word.
(Press the enter key at the prompt to quit.)

The jumble is: jbelum

Your guess: hint
Sorry, that's not it.
Your guess: jumble
That's it! You guessed it!

Great! You did it without a hint
Thanks for playing.


Press the enter key to exit.

当输入是“提示”并直接转到else子句时,为什么while循环都会丢失?

提前感谢您的时间和帮助。

3 个答案:

答案 0 :(得分:2)

问题在于,当您进入while guess != correct and guess != "":循环时,word已完全混乱。因此,在该循环中的所有ifelif语句中,您永远不会让word等于列表中六个单词之一。

要解决此问题,请在correct中将word替换为这些语句:

if guess == "hint" and correct == "python":
    hint = "True"
    print("It's a snake")
    guess = input("Your guess: ")
elif guess == "hint" and correct == "jumble":
    hint = "True"
    print("It's a game")
    guess = input("Your guess: ")
elif guess == "hint" and correct == "easy":
    hint = "True"
    print("It's type of difficulty")
    guess = input("Your guess: ")
elif guess == "hint" and correct == "difficulty":
    hint = "True"
    print("It's type of difficulty")
    guess = input("Your guess: ")
elif guess == "hint" and correct == "answer":
    hint = "True"
    print("It's the opposite of question")
    guess = input("Your guess: ")
elif guess == "hint" and correct == "xylophone":
    hint = "True"
    print("Don't know WTF is that")
    guess = input("Your guess: ")
else:
    print("Sorry, that's not it.")
    guess = input("Your guess: ")

答案 1 :(得分:1)

musical_coder是对的,解决了你的问题。您应该在代码中更改更多内容以使其更好:

不要将字符串用于提示变量,请使用boolean:

代替:

hint = "False"
hint = "True"

使用:

hint = False
hint = True

此外,您可以稍微重写while循环

 guess = input("Your guess: ")

只有一次而不是每次都是。

另外,更改结果打印会导致这样,即使您输入空字符串并退出游戏,也会打印提示信息。

所以看起来像这样:

print("The jumble is:", jumble)
guess = "dummy"
while guess != correct and guess != "":
    guess = raw_input("Your guess: ")
    if guess == "hint" and correct == "python":
        hint = True
        print("It's a snake")
    elif guess == "hint" and correct == "jumble":
        hint = True
        print("It's a game")
    elif guess == "hint" and correct == "easy":
        hint = True
        print("It's type of difficulty")
    elif guess == "hint" and correct == "difficulty":
        hint = True
        print("It's type of difficulty")
    elif guess == "hint" and correct == "answer":
        hint = True
        print("It's the opposite of question")
    elif guess == "hint" and correct == "xylophone":
        hint = True
        print("Don't know WTF is that")
    else:
        print("Sorry, that's not it.")

if guess == correct:
    print("That's it! You guessed it!\n")

    if not hint:
        print("Great! You did it without a hint")
    else:
        print("Dat hint, man")

print("Thanks for playing.")
input("\n\nPress the enter key to exit.")

答案 2 :(得分:0)

这是让您的程序更简单的一种方法:

jumble = ''.join(random.sample(word, len(word)))
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