MVC在一个视图中显示多个表?

时间:2013-10-23 09:47:08

标签: asp.net-mvc razor

我创建了一个父模型insertBreweryModel.cs:

public class InsertBreweryModel
{
    public IList<Breweries> Breweries { get; set; }

    public IList<BreweryData> BreweryData { get; set; }
}

在我看来我引用它:

@model BaPP.Models.InsertBreweryModel

现在我成功地可以使用foreach迭代Breweries中的项目,但是我如何才能显示来自其他tablem的数据,其中id与item.id相同?

@foreach (var item in Model.Breweries)
{
  <tr>
  <td>
    @Html.DisplayFor(modelItem => item.BreweryName)
  </td>
  <td>@Html.DisplayForModel(Model.BreweryData Pseudo: show data from brewerydata.column where id = item.id
  </td>
希望有人可以提供帮助吗?

3 个答案:

答案 0 :(得分:3)

对于可能有同样问题的所有人来说,第一个答案是正确的,但在我看来,我错过了其他数据库。这就是我解决它的方式。

我的模特

namespace BaPP.Models
{
   public class InsertBreweryModel
   {
       public Breweries Breweries { get; set; }

       public BreweryData BreweryData { get; set; }

   }
}

我的控制器

namespace BaPP.Controllers
{
    public class BreweryController : Controller
    {
        private ProjectContext db = new ProjectContext();

        //
        // GET: /Default1/

        public ActionResult Index()
        {            

            var viewModel = from o in db.Breweries join o2 in db.BreweryData on o.BreweryId equals o2.BreweryId where o.BreweryId.Equals(o2.BreweryId) select new InsertBreweryModel { Breweries = o, BreweryData = o2};
            return View(viewModel);
        }

我的观点

@model IEnumerable<BaPP.Models.InsertBreweryModel>

@foreach (var item in Model) {
    <tr>
      <td>
        @Html.DisplayFor(modelItem => item.Breweries.BreweryName)
      </td>
    <td>

       @Html.DisplayFor(modelItem => item.BreweryData.DescriptionText)
    </td>

对于两个评论再次thx: - )

答案 1 :(得分:0)

试试这个:

@foreach (var item in Model.Breweries)
{
  <tr>
  <td>
    @Html.DisplayFor(modelItem => item.BreweryName)
  </td>
  <td>
    @Html.DisplayFor(modelItem => item.tableName.tableFieldname)
  </td>
  </tr>
}

答案 2 :(得分:0)

尝试使用类似的东西

@foreach (var item in Model.Breweries)
{
@Html.DisplayFor(model => item.FieldForBreweries)

foreach (var item1 in Model.BreweryData.Where(x => x.Id == item.Id))
{
@Html.DisplayForModel(item1)
}
}