如何在C#中阅读复杂的XML?

时间:2013-10-23 16:02:55

标签: c# xml

我有以下XML,我需要通过搜索Model Value和StoreName值来获得价格

<?xml version="1.0" encoding="utf-8"?>
<Results>
 <Product>
  <Model>X-180</Model>
  <Prices>
   <Price value="180.0" StoreName="StoreA" />
   <Price value="181.0" StoreName="StoreB" />
   <Price value="181.0" StoreName="StoreC" />
  </Prices>
 </Product>
 <Product>
  <Model>LB621120S</Model>
  <Prices>
   <Price value="2100.0" StoreName="StoreD" />
   <Price value="2120" StoreName="StoreF" />
   <Price value="4050" StoreName="StoreG" />
  </Prices>
 </Product>
</Results>

例如: 如果我运行一个函数来获得Model =“LB621120S”和StoreName =“StoreF”的价格 我应该得到价格:2120

这可以在XmlTextReader中使用吗?

4 个答案:

答案 0 :(得分:3)

此XPath将返回您想要的Price元素:

/Results/Product[Model='LB621120S']/Prices/Price[@StoreName='StoreF']

答案 1 :(得分:1)

使用LINQ:

 XDocument doc = XDocument.Parse(xml);

 var value =
    doc.Descendants("Product")
    .First(p => p.Descendants("Model").First().Value == "LB621120S")
     .Descendants("Price")
      .First(p => p.Attribute("StoreName").Value == "StoreF")
       .Attribute("value").Value;

答案 2 :(得分:1)

试试这个:

var reader = new XmlTextReader(<XmlPathFileName>);
var doc = new XmlDocument();
doc.Load(reader);
reader.Close();

var root = doc.DocumentElement;
        if (root == null)
            return;

var node = root.SelectSingleNode("/Results/Product[Model='LB621120S']/Prices/Price[@StoreName='StoreF']");

答案 3 :(得分:0)

xdoc.Descendants("Product")
    .Where(p => (string)p.Element("Model") == model)
    .Elements("Price")
    .Where(p => (string)p.Attribute("StoreName") == store)
    .Select(p => (decimal)p.Attribute("value"))
    .FirstOrDefault();
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