Question

我有以下脚本 -

select sum(duration) as duration from opr 
       where op in ('GRC','GCQ')
       and timestamp between '20130101000000' and '20130930235959'

我收到了值 - 34459298 秒。我想包括这些限制 - 持续时间

＆lt; =＆＃39; 18000000＆＃39; （秒）应乘以0.14
＆gt;之间的持续时间＆＃39; 18000000＆＃39;和＆lt; =＆＃39; 27000000＆＃39;应该乘以0.11
并且持续时间＆gt; ＆＃39; 27000000＆＃39;应该乘以0.09

我试过这个案例陈述 -

   case when duration <= '18000000' 
        then (duration)*0.14
        when duration > '18000000' and duration <= '27000000'
        then (duration)*0.11
        when duration > '27000000' 
        then (duration)*0.09
          else 0 end as bal

但是，我收到此值 34459298 乘以0.09，因为它大于＆＃39; 27000000＆＃39;，这不是主意。这个想法是这两个操作（＆＃39; GRC＆＃39; GCQ＆＃39;）与上述值相乘的所有秒数。

你能帮我做一下吗？

Answer 1

duration是数字还是字符串？与数字比较会更好，我想：

SELECT
    SUM(
      CASE
        WHEN duration <= 18000000 THEN duration * 0.14
        WHEN duration > 18000000 AND duration <= 27000000 THEN duration * 0.11
        WHEN duration > 27000000 THEN duration * 0.09
        ELSE 0
      END
    ) AS duration
  FROM opr 
WHERE
  op IN ('GRC','GCQ')
  AND timestamp BETWEEN '20130101000000' AND '20130930235959'
;

Answer 2

使用子查询选择特定的持续时间，并按照您的值乘以持续时间，然后使用该子查询的总和。

Answer 3

试试这个：

select sum(case
        when duration <= '18000000' then (duration)*0.14
        when duration > '18000000' and duration <= '27000000' then (duration)*0.11
        when duration > '27000000' then (duration)*0.09
        else 0
    end) as bal
from opr 
where op in ('GRC','GCQ')
    and timestamp between '20130101000000' and '20130930235959'

Answer 4

我想你想这样做

select sum(case when duration <= '18000000' then (duration)*0.14
                when duration > '18000000' and duration <= '27000000' then (duration)*0.11
                when duration > '27000000' then (duration)*0.09
                else 0 end as bal) as duration 
from opr 
where op in ('GRC','GCQ')
and timestamp between '20130101000000' and '20130930235959'

多个聚合函数

4 个答案: