Question

thread_list = thread.objects.select_related().filter(thread_forum_id = current_obj.id).order_by('-thread_date')
            for thread in thread_list:
                count = post.objects.select_related().filter(post_thread_id = thread.id).count()   
                thread.post = count

怎么做？

thread.post = count

^

class thread(models.Model):
    mess = models.CharField(max_length=5000)
    objects = thread_manager()

我想手动将新项目添加到列表中。

Answer 1

您的问题写得不好，但我相信您所寻找的是annotation（docs here）：

from django.db.models import Count
thread_list = thread.objects.select_related().filter(thread_forum_id=current_obj.id) \
    .order_by('-thread_date').annotate(post_count=Count('post_thread_set'))
# I'm just guessing this name: 'post_thread_set'

返回的值不是dicts列表，而是queryset，它是一个可迭代的对象。然后，您可以访问post_count作为属性：

thread_list[0].post_count

Answer 2

你的方式很好。但是存在冲突：

thread_list = thread.objects.select_related().filter(thread_forum_id = current_obj.id).order_by('-thread_date')
            for thread in thread_list:
                count = post.objects.select_related().filter(post_thread_id = thread.id).count()   
                thread.post = count

您的班级名称为主题，您的循环名称类似于班级。对于thread_list中的线程：

就这样做：

for threads in thread_list:
                    count = post.objects.select_related().filter(post_thread_id = threads.id).count()   
                    threads.post = count

或类似的东西。只需更改循环 - 我在单词的末尾添加's'

Django将新项目添加到dict

2 个答案: