Question

您好我正在使用带有单个红外传感器的线跟随器机器人。

我已经提供了模拟客户端+硬件。我正在尝试模拟部分，我必须沿着有效路径移动机器人，直到我在迷宫中找到一个标记。然后停下来并给出坐标x，y，如下所示：＆＃34;在x，y＆＃34;上找到的标记。该坐标由服务器应用程序根据全局坐标系统给出（例如东，西......）你的机器人有一个局部坐标系（例如向左，向右，向前......）。选择开始时机器人的方向并在屏幕上显示实际坐标太。每次运动发送到服务器应用程序之前都会在屏幕上给出必要的机器人方向校正（＆＃34;向左＆＃34;，＆＃34;向前＆＃34;，＆＃34;到右边＆＃34;，＆＃34;转身＆＃34;）然后坐标发送到服务器。例：欢迎来到辛机器人在路口：3,5 取向为：南机器人移动：向左移动机器人去：4,5 ... 令牌发现于：2,1

有两种方法可以在本地或远程服务器上模拟程序，在本地机器上我可以看到迷宫，但在远程服务器上总是给我一个未知的迷宫。

我有两个C档

roboproxy.c

    #include <stdarg.h>
#include "../h/RobotProxy.h"

/// initialized with ROBOT_FAIL
int currentIntersection = ROBOT_FAIL;

#if !defined(vasprintf)
static int vasprintf(char **s, const char *format, va_list ap) {
    /* Guess we need no more than 100 bytes. */
    int n, size = 100;
    va_list save_ap;

    if ((*s = (char*) malloc(size)) == NULL)
        return -1;
    while (1) {
        /* work on a copy of the va_list because of a bug
         in the vsnprintf implementation in x86_64 libc
         */
#ifdef __va_copy
        __va_copy(save_ap, ap);
#else
        save_ap = ap;
#endif
        /* Try to print in the allocated space. */
#ifdef _vsnprintf
        n = _vsnprintf(*s, size, format, save_ap);
#else
        n = vsnprintf(*s, size, format, save_ap);
#endif
        va_end(save_ap);
        /* If that worked, return the string. */
        if (n > -1 && n < size) {
            return n;
        }
        /* Else try again with more space. */
        if (n > -1) { /* glibc 2.1 */
            size = n + 1; /* precisely what is needed */
        } else { /* glibc 2.0 */
            size *= 2; /* twice the old size */
        }
        if ((*s = (char*) realloc(*s, size)) == NULL) {
            return -1;
        }
    }
}
#endif

#if !defined(asprintf)
static int asprintf(char **s, const char *format, ...) {
    va_list vals;
    int result;

    va_start(vals, format);
    result = vasprintf(s, format, vals);
    va_end(vals);
    return result;
}
#endif

/// Set the robot to the specified position
/// @ returns ROBOT_SUCCESS, ROBOT_FAIL or ROBOT_TOKENFOUND
int Robot_Move(int x, int y) {
    char* buffer;
    asprintf(&buffer, "{\"x\":%d,\"y\":%d}", x, y);
    char* query = url_encode(buffer);
    free(buffer);
    char* response = sendAndRecieve(concat(URL, query));

    if (response == NULL) {
        puts("Connection to server failed!");
        return ROBOT_FAIL;
    }

    if (contains(response, "\"code\":1")) {
        puts("Connection declined!");
        return ROBOT_FAIL;
    }

    if (contains(response, "\"code\":2")) {
        puts("Connection blocked!");
        return ROBOT_FAIL;
    }

    if (contains(response, "\"code\":3")) {
        printf("Invalid position! (x=%d, y=%d)\n", x, y);
        return ROBOT_FAIL;
    }

    int foundIntersection = 0;
    bool token = false;

    if (contains(response, "\"north\":true"))
        foundIntersection |= D_N;
    if (contains(response, "\"east\":true"))
        foundIntersection |= D_E;
    if (contains(response, "\"south\":true"))
        foundIntersection |= D_S;
    if (contains(response, "\"west\":true"))
        foundIntersection |= D_W;

    if (contains(response, "\"token\":true"))
        token = true;

    free(query);

    currentIntersection = foundIntersection;
    if (token)
        return ROBOT_TOKENFOUND;

    return ROBOT_SUCCESS;
}

/// Get the intersections of the current node that the robot is at
/// @ returns always the intersection at position x=0,y=0 if Robot_Move was not called first
int Robot_GetIntersections() {
    if (currentIntersection == ROBOT_FAIL)
        Robot_Move(0, 0);
    return currentIntersection;
}

Roboclientsim.C

    #include "../h/Configuration.h"

int main(void) {

    printf("Token: %d\n", Robot_Move(1, 0));
    printf("Intersection: %d\n", Robot_GetIntersections());

    return EXIT_SUCCESS;
}

当我在控制台中运行程序时它给了我Token为1然后在找到任何令牌后它将变为2。

所以在roboclientsim.c中我添加了＆＃34;

 If (Robot_Move()==2) //as Robot_move is returning the %d value for Token
printf("another token found ");

＆＃34;

但是我的编译器给出的问题是，很少有人认为是robot_move，

任何人都可以帮我解决这个问题吗？

Answer 1

Robot_Move有两个参数：

int Robot_Move(int x, int y);

你没有任何争论地称之为。

If (Robot_Move()==2)

那是错误。我怀疑你想做的是：

int main(void) {
    int token = Robot_Move(1, 0);
    printf("Token: %d\n", token);
    printf("Intersection: %d\n", Robot_GetIntersections());

    if (token == 2) 
       printf("another token found ");

    return EXIT_SUCCESS;
}

或者也许：

int main(void) {
    int token = Robot_Move(1, 0);

    if (token == 2) {
       printf("Token: %d\n", token);
       printf("Intersection: %d\n", Robot_GetIntersections());
    } else {
       printf("another token found ");
    }

    return EXIT_SUCCESS;
}

Answer 2

检查方法的原型 int Robot_Move(int x, int y) 调用它时需要提供2个参数。

C Code需要很少的帮助

2 个答案: