有人可以解释这个快速排序方法吗?

时间:2013-11-03 19:38:20

标签: java quicksort

你能解释一下这个快速排序方法吗?我正在尝试将此代码实现到我的程序中,但作者没有解释它的作用或它是如何做到的。还要注意我在高中,所以请尽量让它理解。

我所知道的是它快速排序2-D阵列。我也知道它使用递归来执行它的快速排序。不幸的是,就是这样。任何帮助将不胜感激。

public double[][] quicksort(double[][] array, int key, int down, int top) {
    double[][] a = new double[array.length][2];
    System.arraycopy(array,   0, a, 0, a.length);

    int i = down;
    int j = top;
    double x = a[(down + top) / 2][key];

    do {
      while (a[i][key] < x) {
        i++;
      }
      while (a[j][key] > x) {
        j--;
      }
      if (i <= j) {
        double[] temp = new double[a[i].length];

        for (int y = 0; y < a[i].length; y++) {
          temp[y] = a[i][y];
          a[i][y] = a[j][y];
          a[j][y] = temp[y];
        }
        i++;
        j--;
      }
    } while (i <= j);

    if (down < j) {
      a = quicksort(a, key, down, j);
    }

    if (i < top) {
      a = quicksort(a, key, i, top);
    }

    return a;
  }
}

1 个答案:

答案 0 :(得分:0)

要了解的几件事:

  • array是键值对的数组,按键排序。

  • 此快速排序返回原始数组的副本,而不是更改现有数组。

见评论:

public double[][] quicksort(double[][] array, int key, int down, int top) {
    //create copy of array (the author wanted to return a new one)
    double[][] a = new double[array.length][2];
    System.arraycopy(array,   0, a, 0, a.length);

    int i = down; //lower limit
    int j = top;  //upper limit
    double x = a[(down + top) / 2][key]; //the pivot

    do {
      while (a[i][key] < x) { //skip over smaller elements in beginning
        i++;
      }
      while (a[j][key] > x) { //skip over larger elements in end
        j--;
      }

      //now do some partitioning
      if (i <= j) {
        //create temporary array, for swapping elements
        double[] temp = new double[a[i].length];

        for (int y = 0; y < a[i].length; y++) {
          temp[y] = a[i][y];
          a[i][y] = a[j][y];
          a[j][y] = temp[y];
        }
        i++;
        j--;
      }
    } while (i <= j);

    //if there is a non-empty lower partition, sort that
    if (down < j) {
      a = quicksort(a, key, down, j);
    }

    //if there is a non-empty upper partition, sort that
    if (i < top) {
      a = quicksort(a, key, i, top);
    }

    //return the result
    return a;
  }
}
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