我有两张桌子 -
表1:Types
ID | Type
---+------
1 | type1
2 | type2
3 | type3
4 | type4
5 | type5
6 | type6
表2:Details
ID | Type | EventName | Cost
---+--------+-----------+------
1 | type1 | name1 | 500
2 | type1 | name2 | 500
3 | type2 | name3 | 500
4 | type3 | name4 | 1500
5 | type3 | name5 | 1000
6 | type3 | name6 | 1000
两个表的预期结果:
Type | Number | Cost
-------+--------+--------------
type1 | 2 | 1000
type2 | 1 | 500
type3 | 3 | 3500
type4 | 0 | 0
type5 | 0 | 0
type6 | 0 | 0
我尝试了LEFT JOIN
。但它并没有给我正确的数字。
答案 0 :(得分:1)
SELECT t.Type, count(d.Type), sum(d.cost)
FROM Types t LEFT JOIN Details d ON t.Type=d.Type
group by t.Type,d.Type
答案 1 :(得分:0)
SELECT
t.Type,
count(t.type) as Number,
sum(d.cost) as Cost
FROM
Types t
INNER JOIN Details d
ON t.type=d.type
GROUP BY t.type
答案 2 :(得分:-1)
尝试SELECT * FROM(t.type),(t.EventName) 总和(d.cost)