Question

请帮助我，我在使用api v1.1将图片上传到Twitter时遇到问题它在一个月前工作完美，但它现在不起作用。我正在使用亚伯拉罕twitteroauth https://github.com/abraham/twitteroauth 我在表单标签中使用enctype =“multipart / form-data”作为属性这是我的代码：

             require 'inc/twitter.class.php';   

             if(!empty($_FILES['media']['name'])){    // tweet with media
                  $file_name  = $_FILES['media']['name'];
                  $file_type  = $_FILES['media']['type'];
                  $file_size  = $_FILES['media']['size'];
                  $file_temp  = $_FILES['media']['tmp_name'];
                  $file_error = $_FILES['media']['error'];

                  $handle    = fopen($file_temp,'rb');
                  $image     = fread($handle,filesize($file_temp));
                  fclose($handle);
                  $tweet = new TwitterOAuth($YOUR_CONSUMER_KEY, $YOUR_CONSUMER_SECRET, $row_user_info['access_token_oauth_token'], $row_user_info['access_token_oauth_token_secret']);
                  $result = $tweet->post('statuses/update_with_media',array('media[]' => "@{$image};type={$file_type};filename={$file_temp}",'status' => 'test'));

                  echo '<pre>';
                  print_r($result);
                  echo '</pre>';

结果是：

stdClass Object
(
[errors] => Array
    (
        [0] => stdClass Object
            (
                [code] => 195
                [message] => Missing or invalid url parameter.
            )

    )
)

我不知道那里缺少什么请帮帮我

Answer 1

Abraham twitteroauth与向媒体发送推文有关。你可以在这里找到Twitteroauth的固定版本：

https://github.com/tomi-heiskanen/twitteroauth/blob/77795ff40e4ec914bab4604e7063fa70a27077d4/twitteroauth/twitteroauth.php

使用此库，您必须致电：

$result = $tweet->post('statuses/update_with_media',array('media[]' => "@{$image};type={$file_type};filename={$file_temp}",'status' => 'test'), true);

最后一个参数true表示您正在发送多部分请求。

Answer 2

这项工作对我来说

--- --- HTML

<form action="" method="POST" enctype="multipart/form-data">
    <div>
      <label for="status">Tweet Text</label>
      <textarea type="text" name="status" rows="5" cols="60"></textarea>
      <br />

      <label for="image">Photo</label>
      <input type="file" name="image" />
      <br />
      <input type="submit" value="Submit" />
    </div>
  </form>

--- --- PHP

if (!empty($_FILES)) {
      // we set the type and filename are set here as well
      $params = array(
        'media[]' => "@{$_FILES['image']['tmp_name']};type={$_FILES['image']['type']};filename={$_FILES['image']['name']}",
        'status'  => $_POST['status']
      );

      $dd = $twitteroauth->post('statuses/update_with_media',$params,true);

      var_dump($dd);
}

使用此修改后的库

https://github.com/tomi-heiskanen/twitteroauth/blob/77795ff40e4ec914bab4604e7063fa70a27077d4/twitteroauth/twitteroauth.php

Answer 3

非常感谢，但我编辑代码并立即正常工作

if (!empty($_FILES)) {
    // we set the type and filename are set here as well
                    $handle    = fopen($_FILES['image']['tmp_name'],'rb');
                    $image     = fread($handle,filesize($_FILES['image']['tmp_name']));
                    fclose($handle);
    $params = array(
      'media[]' => "@{$image};type={$_FILES['image']['type']};filename={$_FILES['image']['name']}",
      'status'  => $_POST['status']
    );
    $twitteroauth = new TwitterOAuth($YOUR_CONSUMER_KEY, $YOUR_CONSUMER_SECRET, $row_user_info['access_token_oauth_token'], $row_user_info['access_token_oauth_token_secret']);
    $dd = $twitteroauth->post('statuses/update_with_media',$params,true);

    var_dump($dd);

}

twitter api v1.1 status / update_with_media缺少或无效的url参数

3 个答案: