无法执行sqlite SQL文件来创建数据库

时间:2013-11-08 23:41:41

标签: c++ sql sqlite

我有一个带有长事务的sql(文本文件)来创建数据库。

我正在使用Kompex sqlite c ++库:

// open database
Kompex::SQLiteDatabase *pDatabase = new Kompex::SQLiteDatabase(CT2A(strDBFilename), SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE, 0);

// create statement instance for sql queries/statements
Kompex::SQLiteStatement *pStmt = new Kompex::SQLiteStatement(pDatabase);

strSQLCreateDB=get_file_contents(strSQLFilename).c_str(); // load the SQL file

try {
    pStmt->Sql(strSQLCreateDB);
    pStmt->ExecuteAndFree();        
} catch(Kompex::SQLiteException &exception)
{
    std::cerr << "Exception Occured" << std::endl;
    exception.Show();
}

pDatabase->Close();

创建的数据库为0字节且没有错误。 我对任何示例代码感兴趣,即使没有kompex库,也要执行这个创建db的sql事务。

从sqlite浏览器执行数据库会创建数据库而不会出错。

这是SQL命令文件的一部分

/* Disable Foreign Keys */
pragma foreign_keys = off;
/* Begin Transaction */
begin transaction;

/* Database [scanlog(1)] */
pragma auto_vacuum=0;
pragma encoding='UTF-8';
pragma page_size=1024;

/* Drop table [ApplicationNames] */
drop table if exists [ApplicationNames];

/* Table structure [ApplicationNames] */
CREATE TABLE [ApplicationNames] (
  [Id] INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, 
  [ApplicationName] TEXT, 
  [Icon] TEXT);
CREATE INDEX [IndexApps] ON [ApplicationNames] ([Id], [ApplicationName]);

/* Data [ApplicationNames] */
insert into [ApplicationNames] values(1, 'Windows System', null);
insert into [ApplicationNames] values(2, 'Internet Explorer', null); 
insert into [ApplicationNames] values(3, 'Google Chrome', null);

/* Commit Transaction */
commit transaction;

/* Enable Foreign Keys */
pragma foreign_keys = on;

3 个答案:

答案 0 :(得分:1)

您的问题是Sqlsqlite3_prepare函数只执行字符串中的 first SQL命令。

要在字符串中执行多个命令,您必须使用sqlite3_exec

if (SQLITE_OK != (ret = sqlite3_open_v2(CT2A(strDBFilename), &pDb, SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE, NULL)))
{
    TRACE("Failed to open SQLite conn: %d\n", ret);
    break;
} 

if (SQLITE_OK != (ret = sqlite3_exec(pDb, CT2A(strSQLCreateDB), NULL, 0, NULL)))
{
    TRACE("Failed to execute SQLite script: %d, %s\n", ret, sqlite3_errmsg(pDb));
    break;
}

答案 1 :(得分:0)

这似乎有效:

// open connection to a DB
    if (SQLITE_OK != (ret = sqlite3_open_v2(CT2A(strDBFilename), &pDb, SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE, NULL)))
    {
        TRACE("Failed to open SQLite conn: %d\n", ret);
        break;
    } 

    // prepare the statement
    if (SQLITE_OK != (ret = sqlite3_prepare_v2(pDb, CT2A(strSQLCreateDB), -1, &query, NULL)))
    {
        TRACE("Failed to prepare SQLite script: %d, %s\n", ret, sqlite3_errmsg(pDb));
        break;
    }

    if (SQLITE_OK != (ret=sqlite3_exec(pDb, CT2A(strSQLCreateDB), NULL, 0, NULL)))
    {
        TRACE("Failed to execute SQLite script: %d, %s\n", ret, sqlite3_errmsg(pDb));
        break;
    }

答案 2 :(得分:0)

view.sql有声明

从文件中获取数据库定义,这种方式很容易管理表,视图和触发器的定义:

{
    std::ifstream ifs("view.sql");
    std::string content(
        (std::istreambuf_iterator<char>(ifs) ),        
        (std::istreambuf_iterator<char>())
    );

    size_t n_pos,o_pos=0;
    n_pos = content.find(";");
    while (n_pos!=content.npos) {
        ++n_pos;
        sqlite::execute(con,content.substr(o_pos,n_pos-o_pos).c_str(),true);
        o_pos=n_pos;
        n_pos= content.find(";",o_pos);
    }
}
sqlite::execute(con,"VACUUM;",true);
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