我有一个使用C ++的简单代码(与OpenCV结合使用) 这里的代码(主要)
int main(int argc, char** argv)
{
IplImage* image_input = cvLoadImage("test.jpg", CV_LOAD_IMAGE_UNCHANGED);
IplImage* image_output =cvCreateImage(cvGetSize(image_input),
IPL_DEPTH_8U,image_input->nChannels);
unsigned char *h_out = (unsigned char*)image_output->imageData;
unsigned char *h_in = (unsigned char*)image_input->imageData;
int width = image_input->width;
int height = image_input->height;
h_grayscale ( h_in , h_out ) ;
cvShowImage("Original", image_input);
cvShowImage("CPU", image_output);
cvReleaseImage(&image_input);
cvReleaseImage(&image_output);
waitKey(0);
}
这是灰度函数
void h_grayscale( unsigned char* h_in, unsigned char* h_out){
for (unsigned int i=0; i< width*height; i++){
unsigned int index = i*3;
double temp = 0.3*h_in[index]+0.6*h_in[index+1]+0.1*h_in[index+2];
h_out[i] = (unsigned char)temp;
}
}
但是图像的结果用灰度图像分成3个部分
请告诉我我的代码有什么问题? T_T THX
答案 0 :(得分:0)
您需要编辑代码以仅创建一个通道输出图像,因为它是灰度图像:
IplImage* image_output =cvCreateImage(cvGetSize(image_input), IPL_DEPTH_8U, 1);
此外,通过&#34;使用C ++(使用OpenCV)的简单代码&#34;我想象这样的事情:
int main()
{
Mat image_input = imread("test.jpg");
Mat image_output;
cvtColor(image_input, image_output, CV_BGR2GRAY);
imshow("Original", image_input);
imshow("CPU", image_output);
waitKey(0);
return 0;
}