Question

这是我创建数据库表的代码

public void onCreate(SQLiteDatabase db) {
    String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "("
            + KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT,"
            + KEY_PH_NO + " TEXT" + KEY_CTRL_TYPE + " TEXT,"
            + KEY_USER_NAME + " TEXT,"+ KEY_PASSWORD + " TEXT "
            + ")";
    db.execSQL(CREATE_CONTACTS_TABLE);
}

这是为了添加联系人

void addContact(Accounts accounts) {
    SQLiteDatabase db = this.getWritableDatabase();

    ContentValues values = new ContentValues();
    values.put(KEY_NAME, accounts.getName()); // Contact Name
    values.put(KEY_PH_NO, accounts.getPhoneNumber()); // Contact Phone
    values.put(KEY_CTRL_TYPE, accounts.getControlType()); //
    values.put(KEY_USER_NAME, accounts.getUserName()); //
    values.put(KEY_PASSWORD, accounts.getPassword()); //


    // Inserting Row
    db.insert(TABLE_CONTACTS, null, values);
    db.close(); // Closing database connection
}

我在访问addContact

时遇到此错误

db.addContact(new Accounts(siteName,siteNum,ctype,username,pass));

29206-29206/com.atrolabe.tcpremote1 E/SQLiteDatabase﹕ Error inserting control_type=SHAULA 720 user_name=wetyu phone_number=123455566 password=fhhchhjh name=test android.database.sqlite.SQLiteException: table accounts has no column named control_type (code 1): , while compiling: INSERT INTO accounts(control_type,user_name,phone_number,password,name) VALUES (?,?,?,?,?) at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method)

logcat指向addcontact中的这一行

db.insert(TABLE_CONTACTS, null, values);

Answer 1

问题实际上是初始onCreate()方法。生成的SQL构造不正确，永远不会创建control_type列。见下文：

"CREATE TABLE " + TABLE_CONTACTS + "("
        + KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT,"
        + KEY_PH_NO + " TEXT" + KEY_CTRL_TYPE +    ...

在电话号码字段后，TEXT关键字位于预期的control_type列名称旁边;导致意外的SQL。例如（填写预期值）

CREATE TABLE Contacts (
            ContactID INTEGER PRIMARY KEY,  ContactName TEXT,
            ContactNumber TEXTcontrol_type  ...

要解决此问题，只需正确格式化CREATE_CONTACTS_TABLE字符串。

E / SQLiteDatabase：插入错误，表帐户没有名为control_type的列（代码1）：

1 个答案: