Question

您好，我需要按特定时间段对数据进行分组的最佳解决方案。我需要将月份数据从07:00:00到18:59:59分组，然后从19:00:00到下一天06:59:59。在数据库中有大量数据，因此速度有效的解决方案将是首选。

在查询中插入Shift字母也很棒。有4个班次：A，B，C，D和我有日历表。

Table [Shiftcalendar]:
[ShiftDate] | [SHIFT] | [Nextshift]
2013-11-11  |    N    |     A=B
2013-11-11  |    D    |     C=A
2013-11-10  |    N    |     D=C
....        |   ....  |    ....

列[Shift]表示白天或夜晚，列[Nextshift]表示班次和下一班次。 N表示夜间，从19:00:00到下一天06:59:59，D表示日，从07:00:00到18:59:59。

Table [wrkSpeedInfo]:
[wrkActionDate]     | [wrkSpeed] | [wrkGlueValue] | [x1]
2013-11-11 07:00:35 |     200    |       300      |  20
2013-11-11 07:00:55 |     97     |       255      |  13
2013-11-11 07:01:23 |     127    |       124      |  15
....                |     ....   |       ....     | ....

我需要SUM [wrkSpeed]，[wrkGlueValue]和[x1]。

有人帮助会非常感激:)

PS：不介意我的英语写作技巧，我仍处于改进阶段。

编辑：很长一段时间我做了大量的查询来获取特定的日期和移位数据，但是希望在一个查询中包含所有数据。

WHERE [wrkActionDate] BETWEEN '2013-10-03 07:00:00' AND '2013-10-03 18:59:59'

我可以发布完整的查询但是它占用了大量空间，何时需要解释更多我想要做的事情。

编辑：好的，有人说要发布完整的查询：

SELECT [wrkActionDate]
  ,[wrkCntrId]
  ,DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS MinPassed
  ,SUM([wrkSpeed])*DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS SumWrkSpeed
  ,SUM([wrkGlueValue])*DATEDIFF(second, (SELECT TOP 1 t2.[wrkActionDate] FROM [DW].[dbo].[wrkSpeedInfo] as t2 WHERE [wrkCntrId] = 'S1' AND t2.[wrkActionDate] < t1.[wrkActionDate]  ORDER BY t2.[wrkActionDate] DESC), [wrkActionDate])/60.0 AS SumWrkGlueValue
  ,SUM([x1]) AS SumX1
FROM [DW].[dbo].[wrkSpeedInfo] as t1
WHERE [wrkActionDate] BETWEEN '2013-10-03 07:00:00' AND '2013-10-03 18:59:59' AND [wrkCntrId] = 'S1'
GROUP BY [wrkCntrId], [wrkActionDate]

因此，如果我能在一个查询中获得所有月份数据，那将是很好的，因为现在只获取一个班次的数据。

很高兴获得类似的东西：

[ShiftDate] | [SHIFT] | [Nextshift] | SUM([wrkSpeed]) | SUM([wrkGlueValue]) | SUM([x1])

编辑：他们使用的是MS SQL 2012.无法更改结构或任何内容，只能从DB中选择数据。

Answer 1

如果您想根据您必须的日期汇总所有值 GROUP BY CAST(wrkActionDate AS DATE)

但是您不希望精确地按日期分组，您希望根据您的班次模式进行分组。因此，您可以创建一个字段来计算特定时间内的哪个班次，然后根据该字段进行分组。

SELECT [Shift]
    ,SUM(wrkSpeed) AS wrkSpeed
    ,SUM(wrkGlueValue) AS wrkGlueValue
    ,SUM(x1) AS x1
FROM(
    SELECT w.*,
        CASE WHEN (DATEPART(HOUR, wrkActionDate) >= 7 AND DATEPART(HOUR, wrkActionDate) < 19) 
                THEN LEFT(CAST(wrkActionDate AS DATE),10)+' D' 
                ELSE LEFT(CAST(DATEADD(DAY, -1, wrkActionDate) AS DATE),10)+' N' 
           END AS [Shift]
    FROM [DW].[dbo].wrkSpeedInfo w
) w
GROUP BY [Shift]

SQL组按特定时间段

1 个答案: