PHP注册脚本使用预准备语句

时间:2013-11-13 18:00:10

标签: php mysqli

我有以下注册码,SEEMS正在工作,但实际上并没有将输入的信息插入我的表格。一切运行都没有出现错误,“echo'结束';”正在显示。

修改,更新代码: 现在得到这个错误

  

警告:mysqli_stmt :: bind_param():类型中的元素数   定义字符串与中的绑定变量数不匹配   第19行的C:\ xampp \ htdocs \ ppa \ test.php

这一行:

$insert_stmt->bind_param($email, $password, $random_salt, $user);

PHP:

   <?php
include "includes/db_connect.php";

if (isset($_POST['email'], $_POST['p'])) {
    $email = $_POST['email'];
    //Default user perms
    $perms = "user";

    $password = hash('sha512', $_POST['p']); //Need to add JavaScript to hash password before it gets here
    //Create random salt
    $random_salt = hash('sha512', uniqid(mt_rand(1, getrandmax()), true));

    //Create salted password
    $password = hash('sha512', $password.$random_salt);

    //Add insert to database script
    //Use prepared statements!
    if ($insert_stmt = $mysqli->prepare("INSERT INTO users (email, password, salt, perms) VALUES (?, ?, ?, ?)")) {
        $insert_stmt->bind_param($email, $password, $random_salt, $perms);
        $insert_stmt->execute();
    }
    echo "Email: ".$email."<br />";
    echo "Password: ".$password."<br />";
    echo "Random Salt: ".$random_salt."<br />";
    echo "Permissions: ".$perms."<br />";
}
?>

这是我的db_connect.php页面

<?php
define("HOST", 'localhost');
define("USER", 'ppa_user');
define("PASSWORD", 'password');
define("DATABASE", 'ppa');

$mysqli = new mysqli(HOST, USER, PASSWORD, DATABASE);

if ($mysqli->connect_errno) {
    //No database found, redirect to setup
    $url = "http://".$_SERVER['HTTP_HOST'].'/ppa/setup.php';
    header('Location: '.$url);
}
?>

3 个答案:

答案 0 :(得分:1)

替换以下内容:

//Add insert to database script
    //Use prepared statements!
    if ($insert_stmt = $mysqli->prepare("INSERT INTO users (email, password, salt, perms) VALUES (?, ?, ?, ?)"));
    $insert_stmt->bind_param('ssss', $_POST['email'], $password, $random_salt, $user);

//Execute the prepared query
$insert_stmt->execute();
echo "end";

使用:

//Add insert to database script
//Use prepared statements!
if ($insert_stmt = $mysqli->prepare("INSERT INTO users (email, password, salt, perms) VALUES (?, ?, ?, ?)")) {
    $insert_stmt->bind_param($_POST['email'], $password, $random_salt, $user);
    $insert_stmt->execute();
    echo "end";
}

答案 1 :(得分:1)

检查这个

if ($insert_stmt = $mysqli->prepare("INSERT INTO users (email, password, salt, perms) VALUES (?, ?, ?, ?)"));
$insert_stmt->execute(array($_POST['email'], $password, $random_salt, $user));

答案 2 :(得分:1)

为了回答这个问题,得出结论OP需要使用以下代码:

$insert_stmt->bind_param("ssss", $email, $password, $random_salt, $perms);