Question

select MAX (cast (id as numeric)) from table --whatever value it may return

select 
(row_number ()  over (order by id)) as Number from table  --will start at 1

如何组合这两个，所以无论第一个查询返回什么值，我都可以使用该值并从那里自动增加，以某种方式将两者结合起来（尝试嵌套它们，但不成功）或者我需要...

声明变量
获取我的最大ID值
使我的变量等于
然后将该值/变量放在我的第二个陈述中？

...一样

select 
(row_number ()  over (order by id) + (declared_max_value)) as Number from table

Answer 1

试试这个：

WITH CTE as
(SELECT max(Field) FROM Table)
    SELECT WhatYouWant, cte.m FROM Table2
    INNER JOIN CTE ON 0=0

或者这个：

SELECT *, t.maxField FROM Table1 OUTER APPLY (SELECT max(Field) as maxField FROM Table2) t

Answer 2

declare @maxValue int
select @maxValue = select max(cast (id as integer)) from table

declare @uaerystring varchar(max)
select @queryString = 
'(row_number ()  over (order by id) + '
+ @maxValue +
')as Number from table'
Execute(@queryString)

Answer 3

试试这个：

SELECT
    Seed.ID + ROW_NUMBER() OVER (order by T.ID) as Number,
    T.ID
FROM
    T CROSS JOIN
    (SELECT MAX(ID) AS ID FROM T) AS Seed

工作样本：http://www.sqlfiddle.com/#!3/a14ad/3

Answer 4

DECLARE @T Table (ID int , Value Varchar(20))
INSERT INTO @T (ID, Value)
VALUES (50, 'Value1'), (500, 'Value1'), (100, 'Value1'), (50, 'Value2'), (100, 'Value2'),(500, 'Value2')

;with CTE (Value, ID, rn)
AS
(
SELECT Value, MAX(ID), rn = ROW_NUMBER() OVER (ORDER BY Value ASC)
FROM 
@T
GROUP BY Value
)
SELECT * FROM CTE

如何从表中的最大值自动递增我自己的结果列？

4 个答案: