Question

我从几张桌子中选择：

 SELECT  SUM(S2.F64)   as sumAll
 FROM someTABLE1 S1
 LEFT OUTER JOIN someTABLE2 S2 ON S2.F32 = S1.F32 
 WHERE S2.F01 = '1006'
 and S2.F68='ORDER' AND S1.F67='ITEM'

现在我想从另一个选择中得到S1.F01的值：类似这样的

SELECT S3.F01
FROM someTABLE3 S3
WHERE "something..."

所以我想要这样的事情：

SELECT  SUM(S1.F64) as sumAll, S3.F01  
FROM someTABLE3 S3
LEFT OUTER JOIN someTABLE1 S1 ON S1.F01 = S3.F01
LEFT OUTER JOIN someTABLE2 AS S2 ON S1.F32 = S2.F32 
WHERE S1.F01 = S3_F01
and S2.F1068='ORDER' AND S1.F1067='ITEM'

但是我想获取S3中的所有项目，只需填写条件匹配的sumAll中的列。

我想要这样的东西（伪代码）：

SELECT * from S3
FOR EVERY (S3.F01)
{
    SELECT * FROM S1
    if(S1.F1067='ITEM')
        RETURN S3 AND SUM(S1.F64)
    ELSE 
        RETURN S3
}

有没有这样做？

Answer 1

您是否只是在寻找GROUP BY？

SELECT  SUM(S1.F64) as sumAll, S3.F01  
FROM someTABLE3 S3
    LEFT OUTER JOIN someTABLE1 S1 ON S1.F01 = S3.F01
    LEFT OUTER JOIN someTABLE2 AS S2 ON S1.F32 = S2.F32 
WHERE S2.F1068='ORDER' AND S1.F1067='ITEM'
GROUP BY S3.F01

编辑 - 将where条件移动到连接...

SELECT  SUM(S1.F64) as sumAll, S3.F01  
FROM someTABLE3 S3
    LEFT OUTER JOIN someTABLE1 S1 ON S1.F01 = S3.F01 AND S1.F1067='ITEM'
    LEFT OUTER JOIN someTABLE2 AS S2 ON S1.F32 = S2.F32 AND S2.F1068='ORDER'
GROUP BY S3.F01

SQL Fiddle

Answer 2

不完全确定我完全了解你，但这是一种方法：

SELECT  S3.*, SQ.sumValue
FROM someTABLE3 S3
LEFT JOIN( SELECT F01,SUM(F64)
          FROM someTable1
          WHERE F1067='ITEM'
          GROUP BY F01) SQ ON SQ.F01 = S3.F01
LEFT JOIN someTable1 AS S1 ON S1.F01 = S3.F01
LEFT JOIN someTABLE2 AS S2 ON S1.F32 = S2.F32  AND S2.F1068='ORDER'

您执行内部查询，在SUM(F64) GROUP BY F01上获得table1。这样，当您从LEFT JOIN执行table3时，您将获得所需的table3和K或SUM。

然后对于LEFT JOIN table2，LEFT JOIN首先table1，因为我不知道您是否可以将table2与table3联系起来{{1}} {1}}。

这有点令人困惑，但我希望你理解这种方法

结合两个sql脚本

2 个答案: