Question

以下代码需要按顺序和反向顺序打印数组中的随机数。我有相反的订单打印但由于某种原因我似乎无法按原始顺序打印。我不知道要修改什么。我目前所印刷的是“按顺序”的空白行和“反向订单”的数字。我需要修理什么？谢谢！

public class RandomPrintOut
{
   //-----------------------------------------------------------------
   // 
   //-----------------------------------------------------------------
   public static void main (String[] args)
   {

       int numbers[] = new int [10]; 

       for (int i = 0 ; i < 10 ; i++) 
       { 
       numbers [i] = (int) (Math.random () * 100); 
       }



      System.out.println ("The size of the array: " + numbers.length);

      System.out.println ("The numbers in order:");

      for (int index = numbers.length+1; index <= 10; index++)
          System.out.print (numbers[index] + "  ");

      System.out.println ("\nThe numbers in reverse order:");

      for (int index = numbers.length-1; index >= 0; index--)
         System.out.print (numbers[index] + "  ");
   }
}

Answer 1

对于以下代码：

for (int index = numbers.length+1; index <= 10; index++)

此处index的初始值为 number.length + 1 ，此值为 10+1=11 。 这大于10，因此，在这个for循环中永远不会满足该编码。这就是阵列没有按顺序打印的原因。

您需要按如下方式进行更改：

弗罗姆

for (int index = numbers.length+1; index <= 10; index++)
      System.out.print (numbers[index] + "  ");

到

for (int index = 0; index <10; index++)
        System.out.print(numbers[index] + "  ");

更改后的代码如下：

公共类RandomPrintOut { // ------------------------------------------------ ----------------- // // ------------------------------------------------ ----------------- public static void main（String [] args） {

   int numbers[] = new int [10]; 

   for (int i = 0 ; i < 10 ; i++) 
   { 
   numbers [i] = (int) (Math.random () * 100); 
   }

  System.out.println ("The size of the array: " + numbers.length);

  System.out.println ("The numbers in order:");

  for (int index = 0; index < 10; index++)
      System.out.print (numbers[index] + "  ");

  System.out.println ("\nThe numbers in reverse order:");

  for (int index = numbers.length-1; index >= 0; index--)
     System.out.print (numbers[index] + "  ");

} }

在控制台中打印的结果输出：

The size of the array: 10
The numbers in order:
31  50  49  99  29  54  41  16  7  21  
The numbers in reverse order:
21  7  16  41  54  29  99  49  50  31

Answer 2

仔细查看此循环中index的值

  for (int index = numbers.length+1; index <= 10; index++)
      System.out.print (numbers[index] + "  ");

尝试手动完成并查看它的外观。这应该可以帮助您确定问题。

Answer 3

public class RandomPrintOut {
   //-----------------------------------------------------------------
   // 
   //-----------------------------------------------------------------
   public static void main (String[] args) {

       int numbers[] = new int [10]; 

       for (int i = 0 ; i < 10 ; i++) { 
       numbers [i] = (int) (Math.random () * 100); 
       }



      System.out.println ("The size of the array: " + numbers.length);

      System.out.println ("The numbers in order:");

      for (int index = 0; index <= numbers.length-1; index++) {
          System.out.print (numbers[index] + "  ");
      }

      System.out.println ("\nThe numbers in reverse order:");

      for (int index = numbers.length-1; index >= 0; index--) {
         System.out.print (numbers[index] + "  ");
      }
   }
}

按顺序打印和反向排序

3 个答案: