Question

我有以下字符串。

#0
lock;
faceplayer;
say Hello Player!;
end;
#1
lock;
say I don't want to talk to you.;
end;

我想传递一个int并且让方法返回一个从#int开始的字符串，直到结束为止; 怎么办呢？

Answer 1

尝试这样的事情：

#0.to_s
lock;
faceplayer;
say Hello Player!;  
end;
#1.to_s
lock;
say I don't want to talk to you.;
end;

或者

"#0";
lock;
faceplayer;
say Hello Player!;
end;
"#1";
lock;
say I don't want to talk to you.;
end;

Answer 2

取出那个字符串并拆分'＃'然后你会得到一个数组

前：

String[] split = yourString.split("#");

结果：

0 锁; faceplayer; 说你好玩家！端;

1 锁; 说我不想跟你说话。端;

将你的＃添加回到它的开头，你就可以了。

Answer 3

我想你想要这样的东西。使其具有相当的参数化灵活性。

public static String parse(int from, int to, String str) {
  if(str.indexOf("#" + Integer.toString(to)) > 0) {
      return str.substring(str.indexOf("#" + Integer.toString(from)), str.indexOf("#" + Integer.toString(to)));  
  } else {
      return str.substring(str.indexOf("#" + Integer.toString(from)));
  }
}

Answer 4

不是将文本放入字符串，而是放入文件中。这样，每次更改文本时都不必重新编译代码。我知道这不是您可能已经考虑/解释过的确切解决方案，但它是一个可以满足您的要求/需求的解决方案。希望这会对你有所帮助。

public class YourClass {
    public static void main(String[] args) {
        int tagId = 1;
        System.out.println(searchPrint(tagId));
    }

    private static StringBuilder searchPrint(int tagId) {
        String tag = Integer.toString(tagId);
        StringBuilder result = new StringBuilder();
        try {
            BufferedReader br = new BufferedReader(new FileReader("/tmp/one.txt"));
            try {
                String line = br.readLine();
                boolean display = false;
                // loop through to read each line in the file
                while (line != null) {
                    // set the flag to true so then we can print as soon as you
                    // find it
                    if (line.contains("#" + tag)) {
                        display = true;
                    }
                    // set the flag to false to stop print as soon as the end
                    // tag is found
                    else if (line.contains("end;")) {
                        display = false;
                    }

                    if (display == true) {
                        result.append(line);
                        //System.out.println(line);
                    }
                    line = br.readLine();
                }
            } finally {
                br.close();
            }
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return result;
    }
}

我该怎么剪这个字符串？

4 个答案: