如何测试restful JSON创建实体操作?

时间:2013-11-16 23:25:50

标签: symfony testing functional-testing symfony-2.3

我正在尝试测试我的创建操作。它只是获取json内容传递的数据(应用程序使用backbonejs)并再次验证相应的表单类型。表单仍然指示错误“csrf令牌无效”。测试环境使用MockFileSessionStorage生成csrf标记。我尝试生成令牌,然后将会话cookie与请求一起发送,但它没有用。

贝娄是测试班。

<?php
namespace Company\ServiceBundle\Tests\Controller;


use Liip\FunctionalTestBundle\Test\WebTestCase;
use Symfony\Bundle\FrameworkBundle\Client;
use Symfony\Component\BrowserKit\Cookie;
use Symfony\Component\Form\Extension\Csrf\CsrfProvider\CsrfProviderInterface;

class EntidadeControllerTest extends WebTestCase
{
    public function testCreate()
    {

        $dados = array(
            'nome' => 'Entidade TESTE 01',
            'ativo' => 0,
            '_token' => $this->csrfDefaultToken
        );

        $crawler = $this->client->request(
            'POST',
            '/admin/entidades',
            array(),
            array(),
            array(
               'CONTENT_TYPE'          => 'application/json',
               'HTTP_X-Requested-With' => 'XMLHttpRequest'
            ),
            json_encode(array('cartorio_servico_entidade'=>$dados))
        );

        $this->assertEquals(201, $this->client->getResponse()->getStatusCode());
    }

    /** @var Client $client */
    protected $client;
    /** @var CsrfProviderInterface $csrfProvider */
    protected $csrfProvider;

    /** @var string $csrfDefaultToken */
    protected $csrfDefaultToken;

    protected function setUp()
    {
        $this->csrfProvider = $this->getContainer()->get('form.csrf_provider');
        $this->csrfDefaultToken = $this->csrfProvider->generateCsrfToken('unknown');

        $this->client = static::createClient(
            array(),
            array('PHP_AUTH_USER' => 'admin', 'PHP_AUTH_PW' => '123456')
        );

        // session cookie - necessario para nao dar problema com o CSRF token
        $cookie = new Cookie('PHPSESSID', $this->getContainer()->get('session')->getId(), time() + 3600 * 24 * 7, '/', null, false, false);
        $this->client->getCookieJar()->set($cookie);

        $fixtures = array(
            'Company\ServiceBundle\DataFixtures\ORM\LoadUserData'
        );
        $this->loadFixtures($fixtures);
    }
}

Bellow是动作代码。这真的只是一个简单的验证表单数据并继续。

/**
 * Create new resource or just display the form.
 *
 * @param Request $request
 *
 * @return Response
 */
public function createAction(Request $request)
{
    $config = $this->getConfiguration();

    $resource = $this->createNew();
    $form = $this->getForm($resource);

    if ($request->isMethod('POST') && $form->bind($request)->isValid()) {

        /** @var ResourceEvent $event */
        $event = $this->create($resource);

        if (!$event->isStopped()) {
            return new Response(json_encode('criado'), 201, array('Content-Type' => 'application/json'));
        }
    }

    if ($config->isApiRequest()) {
        return $this->handleView($this->view($form));
    }

    return new Response(json_encode('nao criado'), 404, array('Content-Type' => 'application/json'));
}

1 个答案:

答案 0 :(得分:0)

一种入门方法是将其添加到表单类型类中:

    // TODO: remove this once we have auth working.
    $resolver->setDefaults(array(
        'csrf_protection'   => false,
    ));

显然需要考虑安全性,但这可能有助于新手的发展。

相关问题