bash中两个字符串之间的差异

Question

我有两个包含信息行的字符串。我想获得两个字符串中不同的行。 例： 字符串1：

"This is line1
This is line2
This is line3"

String2的：

"This is line1
This is linex
This is line2"

预期结果：

diff string1 string2 is:
"This is line3"

diff string2 string1 is:
"This is linex"

Answer 1

您可以使用comm：

$ str1="This is line1
> This is line2
> This is line3"
$ str2="This is line1
> This is linex
> This is line2"

$ comm -23 <(echo "$str1" | sort) <(echo "$str2" | sort)
This is line3
$ comm -23 <(echo "$str2" | sort) <(echo "$str1" | sort)
This is linex

Answer 2

你可以用diff

来做你想要的事情

$ str1="This is line1\nThis is line2\nThis is line3"; str2="This is line1\nThis is linex\nThis is line2";
$
$ diff -y -W 30 --suppress-common-lines <(echo -e $str1) <(echo -e $str2)
              > This is linex
This is line3 <

受到这个问题和答案的启发：Bash string difference