HTML.ActionLink方法

时间:2008-10-14 09:16:59

标签: c# .net asp.net-mvc html-helper actionlink

假设我有一个班级

public class ItemController:Controller
{
    public ActionResult Login(int id)
    {
        return View("Hi", id);
    }
}

在不在ItemController所在的Item文件夹中的页面上,我想创建一个指向Login方法的链接。那么我应该使用哪种Html.ActionLink方法以及我应该传递哪些参数?

具体来说,我正在寻找替代方法

Html.ActionLink(article.Title,
    new { controller = "Articles", action = "Details",
          id = article.ArticleID })

在最近的ASP.NET MVC版本中已经退役。

10 个答案:

答案 0 :(得分:467)

我认为你想要的是:

ASP.NET MVC1

Html.ActionLink(article.Title, 
                "Login",  // <-- Controller Name.
                "Item",   // <-- ActionMethod
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这使用以下方法ActionLink签名:

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string controllerName,
                                string actionName,
                                object values, 
                                object htmlAttributes)

ASP.NET MVC2

两个参数已被切换

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { id = article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这使用以下方法ActionLink签名:

public static string ActionLink(this HtmlHelper htmlHelper, 
                                string linkText,
                                string actionName,
                                string controllerName,
                                object values, 
                                object htmlAttributes)

ASP.NET MVC3 +

参数与MVC2的顺序相同,但不再需要id值:

Html.ActionLink(article.Title, 
                "Item",   // <-- ActionMethod
                "Login",  // <-- Controller Name.
                new { article.ArticleID }, // <-- Route arguments.
                null  // <-- htmlArguments .. which are none. You need this value
                      //     otherwise you call the WRONG method ...
                      //     (refer to comments, below).
                )

这可以避免将任何路由逻辑硬编码到链接中。

 <a href="/Item/Login/5">Title</a> 

这将为您提供以下html输出,假设:

  1. article.Title = "Title"
  2. article.ArticleID = 5
  3. 您仍然定义了以下路线
  4. routes.MapRoute(
        "Default",     // Route name
        "{controller}/{action}/{id}",                           // URL with parameters
        new { controller = "Home", action = "Index", id = "" }  // Parameter defaults
    );
    

答案 1 :(得分:29)

我想添加到Joseph Kingry's answer。他提供了解决方案,但起初我无法让它工作,并得到像Adhip Gupta一样的结果。然后我意识到路线必须首先存在,参数需要与路线完全匹配。所以我有一个id,然后是我的路线的文本参数,也需要包括在内。

Html.ActionLink(article.Title, "Login", "Item", new { id = article.ArticleID, title = article.Title }, null)

答案 2 :(得分:17)

您可能希望查看RouteLink()方法。您可以通过字典指定所有内容(链接文本和路由名称除外)。

答案 3 :(得分:14)

我认为约瑟夫翻转了控制器和动作。首先是动作然后是控制器。这有点奇怪,但签名的样子。

为了澄清事情,这是有效的版本(改编约瑟夫的例子):

Html.ActionLink(article.Title, 
    "Login",  // <-- ActionMethod
    "Item",   // <-- Controller Name
    new { id = article.ArticleID }, // <-- Route arguments.
    null  // <-- htmlArguments .. which are none
    )

答案 4 :(得分:11)

这个怎么样

<%=Html.ActionLink("Get Involved", 
                   "Show", 
                   "Home", 
                   new 
                       { 
                           id = "GetInvolved" 
                       }, 
                   new { 
                           @class = "menuitem", 
                           id = "menu_getinvolved" 
                       }
                   )%>

答案 5 :(得分:10)

Html.ActionLink(article.Title, "Login/" + article.ArticleID, 'Item") 

答案 6 :(得分:9)

如果你想穿上所有的花式裤子,可以通过以下方式扩展它以便能够做到这一点:

@(Html.ActionLink<ArticlesController>(x => x.Details(), article.Title, new { id = article.ArticleID }))

您需要将其放在System.Web.Mvc命名空间中:

public static class MyProjectExtensions
{
    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController, TAction>(this HtmlHelper htmlHelper, Expression<Action<TController, TAction>> expression, string linkText, object routeValues)
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    public static MvcHtmlString ActionLink<TController>(this HtmlHelper htmlHelper, Expression<Action<TController>> expression, string linkText, object routeValues, object htmlAttributes) where TController : Controller
    {
        var urlHelper = new UrlHelper(htmlHelper.ViewContext.RequestContext, htmlHelper.RouteCollection);

        var attributes = AnonymousObjectToKeyValue(htmlAttributes);

        var link = new TagBuilder("a");

        string actionName = ExpressionHelper.GetExpressionText(expression);
        string controllerName = typeof(TController).Name.Replace("Controller", "");

        link.MergeAttribute("href", urlHelper.Action(actionName, controllerName, routeValues));
        link.MergeAttributes(attributes, true);
        link.SetInnerText(linkText);

        return new MvcHtmlString(link.ToString());
    }

    private static Dictionary<string, object> AnonymousObjectToKeyValue(object anonymousObject)
    {
        var dictionary = new Dictionary<string, object>();

        if (anonymousObject == null) return dictionary;

        foreach (PropertyDescriptor propertyDescriptor in TypeDescriptor.GetProperties(anonymousObject))
        {
            dictionary.Add(propertyDescriptor.Name, propertyDescriptor.GetValue(anonymousObject));
        }

        return dictionary;
    }
}

这包括Route ValuesHTML Attributes的两个覆盖,您的所有观看次数都需要添加:@using YourProject.Controllers或者您可以将其添加到web.config <pages><namespaces>

答案 7 :(得分:6)

使用命名参数以提高可读性并避免混淆。

@Html.ActionLink(
            linkText: "Click Here",
            actionName: "Action",
            controllerName: "Home",
            routeValues: new { Identity = 2577 },
            htmlAttributes: null)

答案 8 :(得分:1)

使用MVC5,我已经这样做了,它是100%正常工作的代码......

@Html.ActionLink(department.Name, "Index", "Employee", new { 
                            departmentId = department.DepartmentID }, null)

你们可以从中得到一个想法...

答案 9 :(得分:-1)

此类型使用:

@ Html.ActionLink( “的MainPage”, “索引”, “主页”)

MainPage:文本名称 索引:动作视图 主页:HomeController

Base Use ActionLink

<html>
<head>
    <meta name="viewport" content="width=device-width" />
    <title>_Layout</title>
    <link href="@Url.Content("~/Content/bootsrap.min.css")" rel="stylesheet" type="text/css" />
</head>
<body>
    <div class="container">
        <div class="col-md-12">
            <button class="btn btn-default" type="submit">@Html.ActionLink("AnaSayfa","Index","Home")</button>
            <button class="btn btn-default" type="submit">@Html.ActionLink("Hakkımızda", "Hakkimizda", "Home")</button>
            <button class="btn btn-default" type="submit">@Html.ActionLink("Iletişim", "Iletisim", "Home")</button>
        </div> 
        @RenderBody()
        <div class="col-md-12" style="height:200px;background-image:url(/img/footer.jpg)">

        </div>
    </div>
</body>
</html>