Hibernate就像在多对多集合上查询一样

时间:2013-11-20 04:42:45

标签: java sql spring hibernate

我的User实体已映射到user_roles。我想根据User.idroles.name

过滤这些角色

与此SQL查询相同

SELECT ur 
FROM user 
     JOIN user_roles ur 
          ON ur.user_id = user.id 
WHERE user.id = 1 
  AND ur.name like '%admin%';

如何在hibernate中实现这个SQL查询? 如何将参数传递给角色名?

User.java

@Entity
class User {
    @ManyToMany
    @JoinTable(name="user_roles",
        joinColumns=@JoinColumn(
            name="user_id", referencedColumnName="id"),
        inverseJoinColumns=@JoinColumn(
            name="role_id", referencedColumnName="id")
        )
    public Set<Role> getRoles() {
        return roles;
    }
}

2 个答案:

答案 0 :(得分:1)

希望它会有所帮助

select "your_req" from User us join usr.role usr where usr.name like '%admin%' and us.id=1

答案 1 :(得分:0)

HQL完全支持您的需求,您可以创建HQL查询,然后将参数传递给它。以下代码块可能是参考:

Long userId = 1L;
String roleNamePattern = "%admin%";

Query query = session.createQuery("SELECT role FROM User user JOIN user.roles role WHERE user.id = :userid AND role.name LIKE :rolename");
query.setLong("userid", userId);
query.setString("rolename", roleNamePattern);
List<Role> roles = query.list();
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