Question

基本上，我正在尝试填充选择框，但会连接first_name列和last_name列中的值。

我想做什么（不起作用）：

<select ng-model="buyers" ng-options="b.id as (b.first_name + " " + b.last_name) for b in buyers"></select>

工作原理：

<select ng-model="buyers" ng-options="b.id as b.first_name for b in buyers"></select>

Answer 1

报价很重要。它不会使用双引号内的双引号或单引号内的单引号。

工作原理：

<select ng-model="buyers" ng-options='b.id as (b.first_name + " " + b.last_name) for b in buyers'></select>

Answer 2

您可以使用此synthax连接字符串：

xmllint --relaxng user.rng --noout user.xml 
user.xml validates

以下代码段连接ng-options="i.x + ' ' + i.y for i in items"和firstname：

lastname

angular.module('myApp', []);

function MyCtrl($scope) {
  $scope.names = [{firstname: 'Jon', lastname: 'Snow'},
                  {firstname: 'Rob', lastname: 'Stark'},
                  {firstname: 'Ned', lastname: 'Stark'}];
}

_{请注意，括号不是必需，但它可以提高可读性。}

Answer 3

试试这个

<select ng-model="buyers" ng-options="b as (b.first_name + " " + b.last_name) for b in buyers">
</select>

是否可以在Angular ng-options中连接值

3 个答案: