Question

我基本上要做的是，如果用户得分＆gt; = 2，则显示“竖起拇指”，如果用户得分<1则显示“竖起拇指”。 2

这是我试图使用的代码..

 <?php
//Recieves form..Form ID
$fid = $_GET['id'];

//Recieves answers
$answer1= $_POST['answerOne'];
$answer2= $_POST['answerTwo'];
$answer3= $_POST['answerThree'];
$score=0;
?>

<?php //Gets thumbs up if did well, gets thumbs down if not so good
    if ($score>=2){
        echo "<center><img src='Images/thumbsup.png' height='295' width='295' /> </center>";
    }
    elseif ($score<2) {
        echo "<center><img src='Images/thumbsdown.png' height='295' width='295' /> </center>";
    }
    ?>  

<body>

<!--Answers for Quiz 1-->   
    <?php 
    if ($fid == 1){

    if ($answer1 == "B") {$score++;}
    if ($answer2 == "B") {$score++;}
    if ($answer3 == "A") {$score++;}
    }
    ?>

    <?php 
    if ($fid == 1){
        echo "
        <p id='YourScore'> Your score is: </p>
        <p id='YourScore'>$score/3 correct answered </p>";}
    ?>

它会一直显示出“大拇指朝下”。我认为这是因为$ score等于0，并且在将分数添加为用于定义是否放弃竖起大拇指的值之后，其未执行的操作是使用递增的值。

任何帮助将不胜感激。

Answer 1

那是因为你没有检查答案因此得分总是为0而elseif ($score<2)总是为真。

你必须在打印'拇指'

之前检查答案是否正确

Answer 2

正如我的评论所述：你在拇指后计算得分，所以转过身来：

<?php
    //Recieves form..Form ID
    $fid = $_GET['id'];

    //Recieves answers
    $answer1= $_POST['answerOne'];
    $answer2= $_POST['answerTwo'];
    $answer3= $_POST['answerThree'];
    $score=0;
?>

<body>
    <div id="Wrapper">  
        <div id="Container">
            <!--Answers for Quiz 1-->   
            <?php 
            if ($fid == 1) {

                if ($answer1 == "B") {$score++;}
                if ($answer2 == "B") {$score++;}
                if ($answer3 == "A") {$score++;}

            }
            ?>

            <?php 
            //Gets thumbs up if did well, gets thumbs down if not so good
            if ($score >= 2) {
                echo "<img src='Images/thumbsup.png' height='295' width='295' /> ";
            }
            elseif ($score < 2) {
                echo "<img src='Images/thumbsdown.png' height='295' width='295' /> ";
            }

            if ($fid == 1) {
                echo "<p id='YourScore'> Your score is: </p>
                      <p id='YourScore'>$score/3 correct answered </p>";
            }
            ?>

在PHP上竖起大拇指或竖起大拇指

2 个答案: