Question

在我的表courses中，我有几个共享相同academy_id的条目。我正在使用foreach循环来检索结果集中的值。 for循环仅显示一个结果，而不是所有其他共享相同academy_id的结果。如何显示共享相同academy_id的所有行？

表值

+----+------------+----------------------+---------------+------------+
| id | academy_id |     course_name      |  start_date   |  end_date  |
+----+------------+----------------------+---------------+------------+
| 1  |        123 | Biology - Basic      | 2013-11-30    | 2013-12-25 |
| 2  |        123 | Biology - Nutrition  | 2013-11-30    | 2013-12-25 |
| 3  |        345 | Chemistry            | 2013-11-30    | 2013-12-25 |
| 4  |        678 | Calculus             | 2013-11-30    | 2013-12-25 |
+----+------------+----------------------+---------------+------------+

PHP

$academy_id = '123';

$db_select  = $db_con->prepare("
SELECT c.course_name,
       c.course_start_date,
       c.course_end_date
FROM courses c
WHERE c.academy_id = 123
");
if (!$db_select) return false;
    if (!$db_select->execute(array(':academy_id' => $academy_id))) return false;
    $results = $db_select->fetchAll(\PDO::FETCH_ASSOC);
    if (empty($results)) return false;
    foreach ($results as $value){
    $final_result = "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['start_date']."</br><b>End Date: </b>".$value['end_date']."</br>";
    }
print_r($_POST);
}

Curent Result

+----+------------+-------------------+---------------+------------+
| id | academy_id |   course_name     |  start_date   |  end_date  |
+----+------------+-------------------+---------------+------------+
| 1  |        123 | Biology - Basic   | 2013-11-30    | 2013-12-25 |
+----+------------+-------------------+---------------+------------+

通缉所有academy_id = 123显示

+----+------------+----------------------+---------------+------------+
| id | academy_id |     course_name      |  start_date   |  end_date  |
+----+------------+----------------------+---------------+------------+
| 1  |        123 | Biology - Basic      | 2013-11-30    | 2013-12-25 |
| 2  |        123 | Biology - Nutrition  | 2013-11-30    | 2013-12-25 |
+----+------------+----------------------+---------------+------------+

Answer 1

更改

$academy_id = '123';

....

foreach ($results as $value){
    $final_result = "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['start_date']."</br><b>End Date: </b>".$value['end_date']."</br>";
}

的

$academy_id = 123;

.....

$final_result = '';
foreach ($results as $value){
    $final_result .= "<b>Course Name: </b>".$value['course_name']."</br><b>Start Date: </b>".$value['start_date']."</br><b>End Date: </b>".$value['end_date']."</br>";
}

echo $final_result;

Answer 2

（看到其他人的回答我知道我解决了你曾经或可能有过的另一个问题）我不确定我是否完全理解您的要求，但您可以尝试

将您的代码分成两部分

1）第一部分将：

SELECT c.academy_id
FROM courses c
GROUP BY c.academy_id

这将是循环的主要结果

2）上一个循环中的第二部分将执行当前的SQL但不使用硬编码的123，它将使用上一个查询的结果作为值

Foreach循环显示具有相同ID的所有记录

2 个答案: