Question

快速提问很可能非常简单。

基本上，我需要将字符串从obdurate更改为oblite。我知道我可以使用StringBuilder的方法，但我无法在初始字符串后插入任何内容。无论如何还要添加更多字符吗？

我的代码如下

public class SimpleString {

public static void main (String [] args){

StringBuilder s1 = new StringBuilder ("obdurate");

s1.delete(2, 7);
s1.replace(2, 7, "lite");
s1.insert(8,15, "ration");   //the problem line.



System.out.println(s1);

Answer 1

使用StringBuilder。append(String str)

s1.append("ration");

Answer 2

使用append（）：

s1.append("ration");

Answer 3

您可以尝试以下内容：

public class SimpleString {

public static void main (String [] args){

StringBuilder s1 = new StringBuilder ("obdurate");

s1.delete(2, 7);
s1.replace(2, 7, "lite");
s1.append("ration");  

System.out.println(s1);

Answer 4

我需要将字符串从 obdurate 更改为删除。

将indexOf(str)与replace(stIndx, endIndx, replacement)功能一起使用：

StringBuilder builder = new StringBuilder("obdurate it is");
int stIndex = builder.indexOf("obdurate");
int endIndex = stIndex + "obdurate".length(); // Find the end of the replacing string
builder.replace(stIndex, endIndex, "obliteration");

无论如何都要添加更多字符？

使用strBuilder.append(String)函数，其中strBuilder是StringBuilder的实例

Answer 5

s1.delete(2, s1.length());
s1.append("literation");

Answer 6

试试这个

   public static void main(String[] args){

        StringBuilder s1 = new StringBuilder ("obdurate");

        s1.delete(2, 7);
        s1.replace(2, 7, "lite");
        s1.append("ration");

        System.out.println(s1);
    }

Answer 7

假设你想在s1中插入一个字符串，最好的方法是

for (int start = 0, start < 7; start ++) // assuming you wanna insert a string with length 7
    s1.append(" ")
// s1 = "obdurate      " then now you can insert a new string easily
// you can now insert in between (i guess by using insert, you don't just want the string to be added in the end)
s1.insert(3,10, "rationa"); // s1 = "obdrationaurate";

我可以使用StringBuilder扩展字符串吗？

7 个答案: