Question

我想计算两个不同表格中两个datetime列的差异

值类似于2013-10-18 13:09:52.630

我确实喜欢select(a-b)，但它没有返回确切的值。我想根据以上值计算天数。请提出一些建议

Answer 1

您可以使用：

SELECT DATEDIFF(DAY, '2013-10-18 13:09:52.630', '2013-10-21 17:02:52.630')

为这些日期返回3。

如果第一个日期早于第二个日期，则会返回负值（例如-2天），您可以将DATEDIFF包裹在ABS()中以使值始终为正。< / p>

从2个表中获取值：

SELECT DATEDIFF(DAY, t1.Date, t2.Date) As DaysBetween
      ,ABS(DATEDIFF(DAY, t1.Date, t2.Date)) As DaysBetweenAlwaysPositive
FROM t1
INNER JOIN t2 ON t1.Id = t2.Id

关于评论：

SELECT 
    CAST(DiffMins / (60*24) AS VARCHAR) + 'days, ' 
    + CAST((DiffMins%(60*24))/60 AS VARCHAR) + 'hrs, ' 
    + CAST((DiffMins%(60*24))%60 AS VARCHAR) + 'mins ' AS dayhourmin
FROM (
SELECT DATEDIFF(MINUTE, '2013-10-18 13:09:52.630', '2013-10-19 15:12:52.630') AS DiffMins
) a

输出：1days, 2hrs, 3mins

这一切都变得非常混乱，但你可以在2表查询中使用它，如下所示：

SELECT CAST(DATEDIFF(DAY, t1.Date, t2.Date)/(60*24)     AS VARCHAR) + 'days, ' 
    + CAST((DATEDIFF(DAY, t1.Date, t2.Date)%(60*24))/60 AS VARCHAR) + 'hrs, ' 
    + CAST((DATEDIFF(DAY, t1.Date, t2.Date)%(60*24))%60 AS VARCHAR) + 'mins ' AS dayhourmin
FROM t1
INNER JOIN t2 ON t1.Id = t2.Id

这是一个更大的问题，你原来的问题，所以你可能想要发布一个新的，如果这不符合你的需要。

Answer 2

SELECT TIMEDIFF('2009-05-18 15:45:57.005678','2009-05-18 13:40:50.005670');

它适用于mysql。我不知道sql server 2008

计算两个表中两个日期时间列的差异

2 个答案: