我目前在我的网站上有一个所有可能IP地址的目录。在过去的一年里，它一直在从MySQL数据库中提取信息，但显然它是一个巨大的数据库来提取信息。
我在想，由于所有IP地址都在0.0.0.0到255.255.255.255之间，因此应该有一种方法可以在不使用数据库的情况下自动生成数据库，并且只基于此人所在的页面。
每个页面显示1002个IP地址，因此第一页应该是第一个1-1002个可能的IP地址，第二个页面将显示1003-2004个IP地址。
以下是我目前用于该网站的代码：
<?php
/*
Place code to connect to your DB here.
*/
mysql_connect("localhost", "user_name", "password") or die(mysql_error());
mysql_select_db("data_base") or die(mysql_error());
$tbl_name="domain_names"; //your table name
// How many adjacent pages should be shown on each side?
$adjacents = 5;
/*
First get total number of rows in data table.
If you have a WHERE clause in your query, make sure you mirror it here.
*/
$query = "SELECT COUNT(*) as num FROM $tbl_name";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];
/* Setup vars for query. */
$targetpage = "ip.php"; //your file name (the name of this file)
$limit = 1002; //how many items to show per page
$page = $_GET['page'];
if($page)
$start = ($page - 1) * $limit; //first item to display on this page
else
$start = 0; //if no page var is given, set start to 0
/* Get data. */
$sql = "SELECT domains FROM $tbl_name LIMIT $start, $limit";
$result = mysql_query($sql);
/* Setup page vars for display. */
if ($page == 0) $page = 1; //if no page var is given, default to 1.
$prev = $page - 1; //previous page is page - 1
$next = $page + 1; //next page is page + 1
$lastpage = ceil($total_pages/$limit); //lastpage is = total pages / items per page, rounded up.
$lpm1 = $lastpage - 1; //last page minus 1
/*
Now we apply our rules and draw the pagination object.
We're actually saving the code to a variable in case we want to draw it more than once.
*/
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?page=$prev\">< previous</a>";
else
$pagination.= "<span class=\"disabled\">< previous</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?page=$next\">next ></a>";
else
$pagination.= "<span class=\"disabled\">next ></span>";
$pagination.= "</div>\n";
}
?>
<?php
$i = 0;
echo '<table style="table-layout:fixed; width:95%;"><tr>';
while($row = mysql_fetch_array($result))
{
$i ++;
if ($i<=3)
{
echo '<td style="word-wrap: break-word;">
<div><center><a style="text-decoration:none;color:#489FDC;" href="http://ip.mysite.com/'.strtolower($row[domains]).'">'.strtolower($row[domains]).'</a></center></div>
</td>';
}
else
{
echo '</tr><tr>';
echo '<td style="word-wrap: break-word;"><div><center><a style="text-decoration:none;color:#489FDC;" href="http://ip.mysite.com/'.strtolower($row[domains]).'">'.strtolower($row[domains]).'</a></center></div></td>';
$i = 0;
$i++;
}
}
echo '</tr></table><br />';
?>
<?=$pagination?>
我在想什么可以做，有没有人能想到这么做的简单方法？它似乎应该像删除任何与数据库相关的代码一样简单，然后根据某个人所在的页面编号...
对此的任何帮助都将非常感激。
答案 0 :(得分：1)
IPv4地址实际上只是32位整数。您可以使用整数并使用long2ip以“ip格式”转换它们。
您以数字（[pagenumber] * [pagesize]）开始页面，遍历[pagesize]数字并使用long2ip打印它们。
可能的陷阱： 你应该在64位系统上没问题 - 在32位系统上，你必须处理'负数'。 根据您的使用情况，请考虑并非所有可能的地址实际上都是合法的。有所谓的私有范围（未路由），组播等。
答案 1 :(得分：0)
这些方面的某些内容会使这更容易。
$perPage = 1002;
$i = ($page - 1 ) * $perPage;
$end = $page * $perPage;
while($i < $end ) {
$dotIP = long2ip((float)$i);
// Do something with $dotIP;
}