Xcode - 如何制作弹出菜单

时间:2013-11-25 21:27:32

标签: ios xcode popupmenu

我想在Xcode中制作一个弹出菜单。我该怎么做?我希望它看起来很漂亮和专业。

谢谢!

1 个答案:

答案 0 :(得分:22)

以下是使用UIActionSheet在UITextView中显示弹出菜单以响应附件上的longPress的示例。

- (void)attachmentActionSheet:(UITextView *)textView range:(NSRange)range {

    // get the rect for the selected attachment (if its a big image with top not visible the action sheet
    // will be positioned above the top limit of the UITextView
    // Need to add code to adjust for this.
    CGRect attachmentRect = [self frameOfTextRange:range inTextView:textView];

      _attachmentMenuSheet = [[UIActionSheet alloc] initWithTitle:nil
                                                           delegate:self
                                                  cancelButtonTitle:@"Cancel"
                                             destructiveButtonTitle:nil
                                                  otherButtonTitles:@"Copy Image", @"Save to Camera Roll", @"Open in Viewer", nil];

    // Show the sheet
    [_attachmentMenuSheet showFromRect:attachmentRect inView:textView animated:YES];
}

- (void)actionSheet:(UIActionSheet *)actionSheet didDismissWithButtonIndex:(NSInteger)buttonIndex {
    if (actionSheet == _attachmentMenuSheet) {
        //FLOG(@"Button %d", buttonIndex);
        switch (buttonIndex) {

            case 0:
                //FLOG(@" Copy Image");
                [self copyImageToPasteBoard:[_attachment image]];
                break;

            case 1:
                //FLOG(@"  Save to Camera Roll");
                [self saveToCameraRoll:[_attachment image]];
                break;

            case 2:
                //FLOG(@"  Open in Viewer");
                [self browseImage:[_attachment image]];
                break;

            default:
                break;
        }
    }
}

这就是它在iPad和iPhone(iOS7)上的样子

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