Question

我正在尝试构建一个表，其中一个列被选中，我想选择具有从服务器获取的值的选项。我从服务器获得4，但选择的是第一个选项。

$scope.lotteryOptions = {
        data: 'myData',
        enableColumnResize: true,
        keepLastSelected: false,
        enableRowSelection: false,
        columnDefs: [{field: 'field1', displayName: 'field1'},
             {field: 'Status', displayName: 'Status', cellTemplate: selectTableTemplate, enableCellEdit: true},
    };

 var selectTableTemplate = "<select ng-selected=\"{{row.getProperty('Status')}}\">         <option value='1' class='ng-binding'>" + 1+ "</option>" +
                           "<option value='2' class='ng-binding'>" + 2 + "</option>" +
                           "<option value='3' class='ng-binding'>" + 3 + "</option>" +
                           "<option value='4' class='ng-binding'>" + 4 + "</option>" +
                           "<option value='5' class='ng-binding'>" + 5 + "</option>" +
                    "<option value='6' class='ng-binding'>" + 6 + "</option></select>";

html结果是：

 <select ng-selected="4">...</select>

但不是选择4选择

Answer 1

ng-selected应该应用于option代码，而不是select（请参阅the docs）

$scope.lotteryOptions = {
    columnDefs: [
        {field: 'field1'},
        {field: 'Status', cellTemplate: selectTableTemplate, enableCellEdit: true}
    ],
    data: 'myData',
    enableColumnResize: true,
    enableRowSelection: false,
    keepLastSelected: false

};

 var selectTableTemplate = '<select>' +
                           '  <option value="1" class="ng-binding" ng-selected="COL_FIELD == 1">' + 1 + '</option>' +
                           '  <option value="2" class="ng-binding" ng-selected="COL_FIELD == 2">' + 2 + '</option>' +
                           '  <option value="3" class="ng-binding" ng-selected="COL_FIELD == 3">' + 3 + '</option>' +
                           '  <option value="4" class="ng-binding" ng-selected="COL_FIELD == 4">' + 4 + '</option>' +
                           '  <option value="5" class="ng-binding" ng-selected="COL_FIELD == 5">' + 5 + '</option>' +
                           '  <option value="6" class="ng-binding" ng-selected="COL_FIELD == 6">' + 6 + '</option>' +
                           '</select>';

Answer 2

ng-selected已经是一个角度属性，因此无需插入{{ }}：

var selectTableTemplate = "<select>         <option ng-selected=\"row.getProperty('Status') == 1\" value='1' class='ng-binding'>" + 1 + "</option>" +
                           "<option ng-selected=\"row.getProperty('Status') == 2\" value='2' class='ng-binding'>" + 2 + "</option>" +
                           "<option ng-selected=\"row.getProperty('Status') == 3\" value='3' class='ng-binding'>" + 3 + "</option>" +
                           "<option ng-selected=\"row.getProperty('Status') == 4\" value='4' class='ng-binding'>" + 4 + "</option>" +
                           "<option ng-selected=\"row.getProperty('Status') == 5\" value='5' class='ng-binding'>" + 5 + "</option>" +
                    "<option ng-selected=\"row.getProperty('Status') == 6\" value='6' class='ng-binding'>" + 6 + "</option></select>";

注意：这也假设Status是一个值，而不是一个对象。

<强>更新 ng-selected不是select的属性。它只是option的一个属性。

Angularjs ng-grid，选择的单元格未选择为正确的值

2 个答案: