var note : String = "blah"
function OnGUI()
{
if (IsPaused)
{
GUI.Box (Rect (580,20,100,210), "Pause");
if (GUI.Button (Rect (590,130,80,20), "Info"))
{
Debug.Log("I pressed it");
GUI.Button (Rect (450, 200, Screen.width/2, Screen.height/2), info);
}
else if (GUI.Button (Rect (590,160,80,20), "Quit"))
{
Application.Quit();
}
else if(GUI.Button (Rect(590,190,80,35), "Back"))
{
IsPaused = false;
GetComponent(LookAtMouse).enabled = true;
}
}
这是我的GUI功能,你可以看到,我有三个按钮。退出和后退按钮工作正常但是当我点击信息按钮时,什么都不会注册。
我将GUI.Button (Rect (450, 200, Screen.width/2, Screen.height/2), info);
这段代码放在if语句之外,以检查它是否有效,但是当它在语句中时我什么都没得到。
谁能告诉我为什么?
答案 0 :(得分:0)
var displayInfo : boolean = false;
if (IsPaused)
{
GUI.Box (Rect (580,20,100,210), "Pause");
displayInfo = GUI.Toggle(Rect (590,130,80,20), displayInfo, "Info");
{
if(displayInfo)
{
GUI.Button (Rect (450, 200, Screen.width/2, Screen.height/2), info);
}
}
@rutter感谢您的想法,我使用了您的布尔思想并创建了一个切换来检查,如果显示信息,则在切换时创建文本字段的实例