Question

我在继承时遇到配置对象的问题所以我已经

了

baseclass.prototype.activity =function(){ console.log("Im"+activity); }

和继承基类的多个其他对象（比如A和B）。

我想根据A和B的类型配置运行因此，如果是A，则调用run应该将活动设置为Running，与B类似，它可以游泳我正在使用以下工厂方法创建A和B，具体取决于其类型

activityFactoryObject.prototype.makeObj = Object.create(baseclass);
activityFactoryObject.prototype.createObject = function (config) {

    switch (config) {
    case "running":

        this.makeObj = A;
        break;
    case "swimming":

        this.makeObj = B;

        break;
    }
    this.makeObj.prototype = baseclass.prototype;  
    return new this.makeObj(config); 

};

Answer 1

我不确定你的目标究竟是什么，但是如果它们都是从baseClass继承的，唯一的区别就是显示的是什么活动，那么这样就足够了：

baseClass.protoype.activity = function ( activity ) { console.log( "I'm " + activity ); };

var a = new BaseClass(),
    b = new BaseClass();

a.activity( 'Running' ); // -> "I'm Running"
b.activity( 'Swimming' ); // -> "I'm Swimming"

Answer 2

不确定这是否是你所追求的：

var Activity = function(argsObj){
  this.activityType = argsObj.activityType || "Default value";
};
Activity.prototype.doIt = function(){
  console.log("I am " + this.activityType);
};

var Run = function(argsObj){
  //re use Activity initializer
  Activity.apply(this,arguments);
};
Run.prototype=Object.create(Activity.prototype);
Run.prototype.constructor = Run;

var Swim = function(argsObj){
  //re use Activity initializer
  Activity.apply(this,arguments);
};
Swim.prototype=Object.create(Activity.prototype);
Swim.prototype.constructor = Swim;

function activityFactory(argsObj){
  return new window[argsObj.type](argsObj);
}

var r = activityFactory({type:"Run",activityType:"running"});
var s = activityFactory({type:"Swim",activityType:"swimming"});
r.doIt();//I am running
s.doIt();//I am swimming
console.log(r instanceof Run);//true
console.log(s instanceof Swim);//true
console.log(s instanceof Activity);//true
var wrong = activityFactory({type:"Run"});
wrong.doIt();//I am Default value

有关构造函数和原型的更多信息：https://stackoverflow.com/a/16063711/1641941

Javascript继承问题＆amp;基类原型

2 个答案: