Deadlock是否需要两个线程等待彼此的资源?

时间:2013-11-28 01:20:46

标签: java multithreading deadlock

我有这个程序,其中两个线程等待相同的锁定库存对象并导致程序挂起。但Thread1并不是为了锁定Thread2,反之亦然。如果这不是死锁,那么这种情况会怎样?

public class DeadlockSimulator {
    public static void main(String[] args) {

        Stock st = new Stock();
        Runnable p1 = new Producer(st);
        Runnable c1 = new Consumer(st);
        Thread t1 = new Thread(p1);
        Thread t2 = new Thread(c1);
        t1.start();
        t2.start();
    }
}

public class Producer implements Runnable{
    private final Stock st;
    public Producer(Stock st) {
        this.st=st;
    }
    @Override
    public void run() {
        try{
            while(true)
                st.addStock(3);
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
    }
}

public class Stock {
    private int qoh; 
    public Stock() {
    }

    public synchronized int getStock(int required) throws InterruptedException
    {
        int take=0;
        if(qoh> required)
        {
            qoh=qoh-required;
            take=required;
            //notify();
        }
        else
        {
            wait();
        }
        return take;
    }
    public synchronized void addStock(int stocks) throws InterruptedException
    {
        if(qoh >7)
        {
            wait();
        }
        else
        {
            qoh=qoh+stocks;
            System.out.println("Current Stock"+ qoh);
        //  notify();
        }
    }
    public int getorderLevel()
    {
        return this.qoh;
    }
}

public class Consumer implements Runnable {
    private final Stock st;
    public Consumer(Stock st) {
        this.st = st;
    }
    @Override
    public void run() {
        try {
            while (true) {
                int got = st.getStock(5);
                System.out.println("Got =" + got);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

1 个答案:

答案 0 :(得分:0)

你是对的:这不是死锁的例子 这是synchronization的一个示例,它是concurrency control的一种形式 在Java中,生产者/消费者问题通常通过使用BlockingQueue来解决。