我不明白为什么这个查询在android和“Graph Api Explorer”中不起作用
111891332274505?字段= albums.fields(ID,名称,描述,updated_time,CREATED_TIME,cover_photo)
错误代码
错误代码:2500错误mensaje:{HttpStatus:400,errorCode:2500, errorType:OAuthException,errorMessage:语法错误“预期结束 字符串而不是“?”。“在字符6: 照片?=的access_token XXXXXXXXXXXX}
代码
public void getAlbumFacebook () {
Request request = new Request(session, "/111891332274505?fields=albums.fields(id,name,description,updated_time,created_time,cover_photo)", null, HttpMethod.GET, new Request.Callback() {
@Override
public void onCompleted(Response response) {
GraphObject graphObject = response.getGraphObject();
FacebookRequestError error = response.getError();
if (error != null) {
DebugLog.log("Error code: " + error.getErrorCode() + " Error mensaje: " + error.toString());
}
if (graphObject != null) {
JSONArray jsonArray = (JSONArray) graphObject.getProperty("data");
DebugLog.log("JSON Facebook "+ jsonArray.toString());
} else {
DebugLog.log("Es null");
}
}
});
Request.executeBatchAsync(request);
}
解
我已经能够解决我可以推断出的问题是“请求”类无法查询插入的字段。
最后,我所做的是建立网址并通过网址请求数据。
构建网址
String id = "111891332274505";
String url = "https://graph.facebook.com/" + id + "/albums?access_token=" + session.getAccessToken() + "&fields=id,name,description,updated_time";
代码请求
public JSONObject getRequestFromUrl (String url) {
try {
httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(get);
HttpEntity responseEntity = httpResponse.getEntity();
is = responseEntity.getContent();
DebugLog.log("Estoy aqui");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
Log.e("JSON", json);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return jObj;
}
答案 0 :(得分:7)
access_token
参数前面应该有&符号& 。但是现在,在该参数之前附加了?。问题是代码的一部分是在网址中附加?而不是& 。
答案 1 :(得分:0)
通过RestFB for java,您可以使用Parameter
类。
Parameter.with("fields", "albums.fields(id,name,description,updated_time,created_time,cover_photo")
。 (API可能会改变)
答案 2 :(得分:-1)
我遇到了同样的问题,但使用GraphRequest类,所以我会为它写。
GraphRequest会像这样制作网址
browser.executeScript("arguments[0].scrollIntoView();", basePage.techSpecContainer.getWebElement());
而不是
...facebook.com/111891332274505?fields=albums...?access_token=...
应该如此。
解决方案:
...facebook.com/111891332274505?fields=albums...&access_token=...