Question

我需要编写一个基本的t-sql函数 f ，它接收以下参数：

(Id int, CustomerId int, Delay int)

并为 f（1,125,32）创建以下xml，稍后将其插入到表中的xml列中：

<content>   
<column name="Id">1</column>   
<column name="CustomerId">125</column>   
<column name="Delay">125</column>   
</content>

有关如何解决问题的任何想法？

Answer 1

DECLARE @Id int, @CustomerId int, @Delay int
SELECT  @Id = 1, @CustomerId = 125, @Delay = 32;

-- Solution #1
SELECT  CONVERT(XML,N'').query(
N'<content>   
<column name="Id">{sql:variable("@Id")}</column>   
<column name="CustomerId">{sql:variable("@CustomerId")}</column>   
<column name="Delay">{sql:variable("@Delay")}</column>   
</content>');

-- Solution #2
            SELECT  'Id' AS '@name', @Id AS 'text()'
UNION ALL   SELECT  'CustomerId',   @CustomerId
UNION ALL   SELECT  'Delay',        @Delay
FOR XML PATH('column'), ROOT('content');

-- Solution #3
SELECT *
FROM 
(
    SELECT @Id AS Id, @CustomerId AS CustomerId, @Delay AS [Delay]
) src
UNPIVOT( [@name] FOR [text()] IN ([Id], [CustomerId], [Delay]) ) unpvt
FOR XML PATH('column'), ROOT('content');

-- Solution #4
SELECT
(
    SELECT  @Id AS Id, @CustomerId AS CustomerId, @Delay AS [Delay]
    FOR XML RAW, TYPE
).query
('
    <content>
    {for $i in //@*
        return <column name="{local-name($i)}">{string($i)}</column>}
    </content>
');

Answer 2

select *
from (values
    (@Id, 'Id'), (@CustomerId, 'CustomerId'), (@Delay, 'Delay')
) as a([@Name], [text()])
for xml path('column'), root('content')

<强> sql fiddle demo

使用列名作为元素创建xml的函数

2 个答案: