Question

大家好，我是Arduino世界的新手，我在Arduino RAM中存储临时值时遇到问题，所以我想我会用PROGMEM将它们存储在闪存中。我试图存储2字节数组但我不能让它们存储后显示。经过一些测试后，我不能让串行打印正常工作，但如果在同一时间，有人可以更好地解释PROGMEM将有所帮助。到目前为止我的代码是：

#include <avr/pgmspace.h>
struct GRID{
  boolean isOn;
  uint16_t color;
  uint8_t X;
  uint8_t Y;
};

GRID landed[10][22];
GRID falling[22][10];

//PROGMEM prog_uint8_t xAxis[] = {1,2,3,4,5,6,7,8,9,10};
//PROGMEM prog_uint8_t yAxis[] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22};

uint8_t xAxis[] = {1,2,3,4,5,6,7,8,9,10};
uint8_t yAxis[] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22};

void iniLanded(){
  for(int i = 0; i < 10; i++)
    for(int j = 0; j < 22; j++){
      landed[i][j].color=0x0000;
      landed[i][j].X = xAxis[i];
      landed[i][j].Y = yAxis[j];
    }
}

void iniFalling(){
  for(int i = 0; i < 22; i++)
    for(int j = 0; j < 10; j++){
      falling[i][j].color=0x0000;
      falling[i][j].X = xAxis[j];
      falling[i][j].Y = yAxis[i];
    }
}

void printLanded(){
  for(int i = 0; i < 10; i++)
    for(int j = 0; j < 22; j++){
      Serial.print(landed[i][j].X); Serial.print(" "); Serial.println(landed[i][j].Y);
    }
}

void printFalling(){
  for(int i = 0; i < 22; i++)
    for(int j = 0; j < 10; j++){
      Serial.print(landed[i][j].X); Serial.print(" "); Serial.println(landed[i][j].Y);
    }
}

void setup(){
  Serial.begin(9600);
  iniLanded();
  iniFalling();

}

void loop(){
  Serial.println(F("Hello World!"));
  delay(100);
  /*printLanded();
  delay(100);
  printFalling();
  delay(100);*/
}

Answer 1

诀窍在于你从flash调用的方式。请参阅我的示例this is where I define，就像您的评论代码一样。这是您回拨数据的地方。注意使用pgm_read_word_near和deference＆amp;。对于字节，单词等有其他类似函数found here ...

如何使用PROGMEM在Arduino闪存中存储字节数组？

1 个答案: