Question

以下是我的意见：

<!DOCTYPE html>
..........
<div class="content">
      <div class="stream-item-header">
          <a class="account-group js-account-group js-action-profile js-user-profile-link js-nav" href="https://twitter.com/jimcramer" data-user-id="14216123">
    <img class="avatar js-action-profile-avatar" src="Twitter%20_%20Search%20-%20%23tsla_files/988b4c2369623b634782f4c0469ec38f_normal.jpg" alt="">
    <strong class="fullname js-action-profile-name show-popup-with-id">Jim Cramer</strong>
    <span>‏</span><span class="username js-action-profile-name"><s>@</s><b>jimcramer</b></span>
  </a>
       <small class="time">
    <a href="https://twitter.com/jimcramer/status/405348028417994752" class="tweet-timestamp js-permalink js-nav js-tooltip" title="3:51 PM - 26 Nov 13"><span class="_timestamp js-short-timestamp " data-time="1385477475" data-long-form="true">26 Nov</span></a>
</small>
      </div>
      <p class="js-tweet-text tweet-text">Love this spirited &amp; rigorous <a href="https://twitter.com/search?q=%24TSLA&amp;src=ctag" data-query-source="cashtag_click" class="twitter-cashtag pretty-link js-nav" dir="ltr"><s>$</s><b>TSLA</b></a> defense ! RT <a href="https://twitter.com/InfennonLabs" class="twitter-atreply pretty-link" dir="ltr"><s>@</s><b>InfennonLabs</b></a>: Why are these idiots selling <a href="https://twitter.com/search?q=%23tsla&amp;src=hash" data-query-source="hashtag_click" class="twitter-hashtag pretty-link js-nav" dir="ltr"><s>#</s><b><strong>tsla</strong></b></a> are they that blind? <a href="https://twitter.com/jimcramer" class="twitter-atreply pretty-link" dir="ltr"><s>@</s><b>jimcramer</b></a></p>
      <div class="stream-item-footer">
<div class="context">
      <span class="metadata with-icn">
        <i class=" badge-top"></i>Favorited 5 times</span>
</div>
...........
</html>

例如，此“输入”位于我的input变量中。

这是我的代码：

  start_link = input.find(' <p class="js-tweet-text tweet-text" ')

如果我运行它，我将收到以下错误：

  start_link = input.find('<p class="js-tweet-text tweet-text" ')
TypeError: Type str doesn't support the buffer API

我该如何解决这个问题？

注意：输入变量的类型是：class 'bytes'

Answer 1

您无法使用bytes.find()在str对象中查找bytes对象（因为它们的类型不同，str不能在bytes内{ {1}}）。
但是，您可以在其中查找字节对象。这应该有效：

start_link = input.find(b' <p class="js-tweet-text tweet-text" ')

顺便说一下，如果要解析html，你应该使用html解析器。

Answer 2

您还可以将来自输入的数据作为str对象，如下所示：

url = "http://www.google.com"
req = request.Request(url)
response = request.urlopen(req)
page = str(response.read()) # make it a str object
print(page[page.find('id='):]) # now you don't need a b in front of your string

TypeError：类型str不支持缓冲API＃find方法？

2 个答案: